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sergiy2304 [10]
2 years ago
5

plesee help me do I need it under 25min and don't answer if you don't know or else u will be reported thank you (◔‿◔)​

Mathematics
1 answer:
34kurt2 years ago
3 0

Answer:

l = 2.25 cm

Step-by-step explanation:

given l is inversely proportional to w² then the equation relating them is

l = \frac{k}{w^2} ← k is the constant of proportion

(i)

to find k use the condition w = 1.5 , l = 16 , then

16 = \frac{k}{1.5^2} = \frac{k}{2.25} ( multiply both sides by 2.25 )

36 = k

l = \frac{36}{w^2} ← equation of proportion

(ii)

when w = 4 , then

l = \frac{36}{4^2} = \frac{36}{16} = 2.25 cm

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Answer: 4.7 is 10 as much as the number 0.47.

If you multiply 0.47 x 10 it will equal 4.7

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PLZ HELPPPPP
QveST [7]

Use the quadratic formula with a = 2, b = -5, and c = 1



x = -b ± sq rt b2 - 4ac
-------------------- <---------- Please note: sq rt is over entire expression of b^2 - 4ac
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-------------------------------- <---------Please note: sq rt is over entire expression (-5)2 + 4(2)(1)
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x = 5 ± √17
---------
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x = 5 + 1√17 OR x = 5 + -1√17
--- --- --- ----
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Answer: x = 5 + 1√17 OR x = 5 + -1√17
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3 years ago
Determine the zeros of the function <br> 5) y=-x² + 2x + 1
Rus_ich [418]
<h3>Zeros of function are x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}</h3>

<em><u>Solution:</u></em>

<em><u>We have to find the zeros of the function</u></em>

y = -x^2 + 2x+1

Find the zeros of function:

-x^2 + 2x+1 = 0\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

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Thus zeros of function are x = 1 + \sqrt{2} \text{ and } x = 1 - \sqrt{2}

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umka2103 [35]

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