3/2x-7=-11
We move all terms to the left:
3/2x-7-(-11)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
We add all the numbers together, and all the variables
3/2x+4=0
We multiply all the terms by the denominator
4*2x+3=0
Wy multiply elements
8x+3=0
We move all terms containing x to the left, all other terms to the right
8x=-3
x=-3/8
x=-3/8
A+B+C+D+E=540°
4X+5+7X+6X+10+5X-5+4X+10=540
26X = 520
X = 520 : 26 = 20°
E = 4X + 10 = 80 + 10 = 90 °
Answer:
We can think that the line of the kite is the hypotenuse of a triangle rectangle, and the altitude is one of the cathetus of the triangle.
And we know that it makes an angle of 65° with the horizontal (i guess this is measured between the hypotenuse and the horizontal adjacent to the kite.
This angle is complementary to the top angle of our triangle rectangle, such that A + 65° = 90°
A = 90° - 65° = 25°
Then the altitude of the kite is the adjacent cathetus to this angle.
We can use the relation:
sin(A) = Adjacent cathetus/hypotenuse.
Sin(25°) = X/350ft
Sin(25°)*350ft = X = 147.9m
Order the following numbers from greatest to least: 2, -1 , 2.58, -1.65. -1, -1.65, 2, 2.58 2.58, 2, -1.65, -1 2.58, 2, -1 , -1.
saw5 [17]
2.58, 2.58, 2.58, 2.58, 2.58, 2, 2, 2, 2, 2, -1, -1, -1, -1, -1, -1.65, -1.65, -1.65, -1.65, -1.65.
