The correct answer is C. Hope this helps.
Answer:
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Step-by-step explanation:
Confidence interval for the proportion of people who own a tablet:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

99% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

Percentage:
Multiply the proportion by 100.
0.7159*100 = 71.59%
0.8841*100 = 88.41%
The 99% confidence interval for the percentage of people who own a tablet computer is between 71.59% and 88.41%
Convert to a decimal which would be 0.55 (11/20).
Then you want to multiply 0.55 by 100 (which is a whole number, all % is going to come from 100) to convert to a full % -> 0.55*100
Then you will simplify 0.55*100
You answer will be 55%.
Answer:
so the lowest term is 1/10
hope this helps u
Answer:
x=1.65
Step-by-step explanation:
First switch sides
4x-8=3.6-2-3
Then subtract 3.6 - 2 - 3
4x-8=-1.4
Add 8 to both sides
4x-8+8=-1.4+8
simplify
4x=6.6
Divide both sides by 4
4x/4 - 6.6/4
The simplify again
x=1.65