Question

A teacher covered the exterior of a rectangular prism-shaped box that measured 8 inches by 9 inches by 10 inches using one sheet of rectangular-shaped wrapping paper that measured 2 feet by 3 feet. There were no gaps or overlapping paper. How many square inches of wrapping paper were left over? Choose an answer

Answer 1

Answer:

380 square inches

Step-by-step explanation:

We are given the measurements of the Rectangular Prism as

8 inches by 9 inches by 10 inches

Where based on the order of arrangement:

8 inches = Length

9 inches= Width

10 inches = Height

Step 1

Find the amount of wrapping paper needed

Perimeter = 2L + 2W

= 2 × 8 + 2 ×9

= 16 + 18

= 34 inches

Base = L × W

= 8 × 9

= 72 inches

Surface Area of the Rectangular Prism =PH + 2B

Where P = Perimeter

H = Height

B = Base

= 34 × 10 + 2× 72

= 340 + 144

= 484 square inches

The area of the Rectangular prism = 484 square inches

Step 2

So we were told that she used wrapping paper the measured 2 feet by 3 feet.

We would convert the values in feet to inches

1 ft = 12 inches

Length = 2 ft = 2 × 12 = 24 inches

Width = 3 ft = 3 × 12 = 36 inches

We find the area of the wrapping paper

Length × Width = 24inches × 36 inches = 864 square inches.

Step 3

The amount of square inches of wrapping paper left over is calculated as:

Area of the wrapping paper used - Area of the Rectangular prism

= 864 square inches - 484 square inches

= 380 square inches.

Therefore, the amount of square inches of wrapping paper left over is 380 square inches.