A triangle has an area of 36 square units. Its height is 9 units.

Eduardwww [97]

9514 1404 393

Answer:

-0.16

Step-by-step explanation:

The 'a' value can be found by looking at the difference between the y-value of a point 1 unit from the vertex, and the y-value of the vertex.

Here, that is a negative fraction of a unit. If we assume the value is a rational number that can be accurately determined from this graph, then we can find it by looking for a point where the graph crosses a grid intersection. It looks like such grid points are (-7, 0) and (3, 0). The vertex is apparently (-2, 4), so the vertex form of the equation is ...

y = a(x +2)^2 +4

Using the point (3, 0), we have ...

0 = a(3 +2)^2 +4 . . . . . fill in the values of x and y

-4 = 25a . . . . . . . . . . subtract 4; next, divide by 25

a = -4/25 = -0.16

7 0

2 years ago

Sonny substituted 5 for x in the proportion 16/x=48/15 and cross multiplied to get 240=240. Why is this?

Mashutka [201]

Because 16/5 and 48/15 are equivalent fractions

7 0

3 years ago

Read 2 more answers

Can someone help me on 6?

fomenos

Answer:

66600 ft

Step-by-step explanation:

First draw a rectangle and draw a diagonal line in the middle. The line makes two triangles, and the line itself is the hypotenuse. So, to find hypotenuse, the formula is:

a^2 + b^2 = c^2

The variable c defines the hypotenuse. Therefore:

a = 150

b = 210

Let's solve:

150^2 + 210^2 = c^2

22500 + 44100 = c^2

66600 = c^2

Therefore, in conclusion, the result we are getting is 66600 ft.

Hope This Helps!

6 0

2 years ago

Read 2 more answers

A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f

mestny [16]

Answer:

The value is $W= 2640 \ ft \cdot lb$

Step-by-step explanation:

From the question we are told that

The weight of the bucket is $F = 5 lb$

The depth of the well is $x_1 = 60 \ ft$

The weight of the water is $W_w = 42 lb$

The rate at which the bucket with water is pulled is $v = 1.5 \ ft/s$

The rate of the leak is $r = 0.15 lb/s$

Generally the workdone is mathematically represented as

$W = \int\limits^{x_1}_{x_o} {G(x)} \, dx$ ]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

$G(x) = F + (W_w- Ix)$

Here I is the rate of water loss in lb/ft mathematically represented as

$I = \frac{r}{v}$

=> $I = \frac{0.15 }{1.5 }$

=> $I = 0.1$

So

$G(x) = 5 + (42- 0.1x)$

=> $G(x) = 47- 0.1x)$

So

$W = \int\limits^{60}_{0} {47- 0.1x} \, dx$ ]

=> $W = [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.$

=> $W= [47(60) - 0.05(60)^2]$

=> $W= 2640 \ ft \cdot lb$

7 0

3 years ago

Explain your answer !! Have a nice day Will give braisnlt

lora16 [44]

Answer:

The equations are:

$4H + 3P = 13.75$

$2H + 5P = 11.25$

$Hotdog = 2.50$

$Pretzel = 1.25$

Step-by-step explanation:

Let:

$H = hot\ dog$

$P =Pretzel$

For Tina:

$4H + 3P = 13.75$

For Doug:

$2H + 5P = 11.25$

Solving for the price of both items:

We have:

$4H + 3P = 13.75$ --- (1)

$2H + 5P = 11.25$ --- (2)

Multiply (2) by 2

2 * ( $2H + 5P = 11.25$ )

-------------------

$4H + 10P = 22.50$ --- (3)

Subtract (3) from (1)

$4H + 3P = 13.75$

$4H + 10P = 22.50$

----------------------

$4H - 4H + 3P - 10P = 13.75 - 22.50$

$3P - 10P = 13.75 - 22.50$

$-7P = -8.75$

Solve for P

$P = \frac{-8.75}{-7}$

$P = 1.25$

Substitute 1.25 for P in (2)

$2H + 5P = 11.25$

$2H + 5 * 1.25 = 11.25$

$2H + 6.25 = 11.25$

Collect Like Terms

$2H = 11.25-6.25$

$2H = 5$

Solve for H

$H = \frac{5}{2}$

$H = 2.50$

3 0

2 years ago