And
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So :
And
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So to find g(x) , we must find the inverse of f(x) .
Let's do it .....
Subtract the sides of the equation minus 1
Divided the sides of the equation by 8
From the sides of the equation, we take the radical with interval 3
![\sqrt[3]{ \frac{y - 1}{8} } = x \\](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7By%20-%201%7D%7B8%7D%20%7D%20%3D%20x%20%5C%5C%20%20)
![\sqrt[3]{ \frac{1}{8}(y - 1) } = x \\](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%20%5Cfrac%7B1%7D%7B8%7D%28y%20-%201%29%20%7D%20%3D%20x%20%5C%5C%20%20)
![\frac{1}{2} \sqrt[3]{y - 1} = x \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%5Csqrt%5B3%5D%7By%20-%201%7D%20%3D%20x%20%5C%5C%20%20%20)
![\frac{ \sqrt[3]{y - 1} }{2} = x \\](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7By%20-%201%7D%20%7D%7B2%7D%20%3D%20x%20%5C%5C%20%20)
So ;
![{f}^{ - 1}(x) = \frac{ \sqrt[3]{x - 1} }{2} \\](https://tex.z-dn.net/?f=%20%7Bf%7D%5E%7B%20-%201%7D%28x%29%20%3D%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7Bx%20-%201%7D%20%7D%7B2%7D%20%5C%5C%20%20%20%20)
Now we find g(x) which is :
![g(x) = \frac{ \sqrt[3]{x - 1} }{2} \\](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%20%5Cfrac%7B%20%5Csqrt%5B3%5D%7Bx%20-%201%7D%20%7D%7B2%7D%20%5C%5C%20%20)
_________________________________
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
So a 30 year old professor would be 2.4 standard deviations less than the mean.
{6y^3+2y^2}{10y^2}= 10y 2 6y 3 +2y 2 =start fraction, 6, y, cubed, plus, 2, y, squared, divided by, 10, y, squared, end fracti
malfutka [58]
Answer:
y=0
Step-by-step explanation:
Definition:An expression is undefined at the value(s) at which the denominator equals zero.
We are to determine the value of y that makes the expression undefined.
We equate the denominator to zero and solve for y.
Therefore, at y=0, the given expression is undefined.
Surface area of cylinder is 2 (pi)rh+2(pi)r^2
this is the area of the side [(2 (pi)rh] and the two circles together [2 (pi)r^2]
122. r=24
h=15
2 (3.14)24×15+2 (3.14)24^2
6.28×24×15+6.28×24^2
2260.8+3617.28
5878.08mm
123. r=5
h=8
2 (3.14)5×8+2 (3.14)5^2
6.28×5×8+6.28×5^2
251.2+157
408.2cm
124. the surface area of a cylinder that has a hole is going to be
surface area of big cylinder-2small area circles (the holes) + the area of the holes sides
hopefully that isn't too confusing
big radius: 8
height: 14
little radius: 2.5
height: 14
2 (3.14)8×14+2 (3.14)8^2
6.28×8×14+6.28×8^2
703.36+401.92
1105.28in (area of big cylinder)
2 (3.14)2.5^2 (two small holes)
6.28×2.5^2
39.25in (area of holes)
2 (3.14)×2.5×14 (area of side)
6.28×2.5×14
219.8in
1105.28-39.25+219.8
1066.03+219.8
1285.83in total surface area
125. h=20
r=6 since diameter is a foot or 12 in, half of that is 6
2 (3.14)6×20+2 (3.14)6^2
6.28×6×20+6.28×6^2
753.6+226.08
979.68in
126. first radius= 10
first height = 6
second radius= 6
second height= 10
2 (3.14)10×6+2 (3.14)10^2
6.28×10×6+6.28×10^2
376.8+628
1004.8in (surface area of first cylinder)
2 (3.14)6×10+2 (3.14)6^2
6.28×6×10+6.28×6^2
376.8+226.08
602.88in (surface area of second cylinder)
1004.8-602.88= 401.92
the surface area of the cylinder with radius 10 and height 6 is GREATER that the surface area of the cylinder with radius 6 and height 10..
by 401.92in
Answer: See explanation
Step-by-step explanation:
Let the number of callories that are in one cheeseburger be = x
Let the number of calories that are in one medium frys be = y
Therefore, the question can be formed into an expression as:
Jerry = 1x + 1y = 1200
Joe = 2x + 1y = 1260
x + y = 1200 ....... i
2x + y = 1260 ....... ok
Subtract equation i from ii
x = 60
Therefore, number of callories that are in one cheeseburger is 60 calories
Since x + y = 1200
60 + y = 1200
y = 1200 - 60
y = 1140 calories
The number of calories that are in one medium frys is 1140 calories
