Find the area of the triangle on top
A=(.5)(Base)(Height)
A=(.5)(15)(9)
A=67.5
In the rhombus below you can move the corner triangle to the other side to transform it into a rectangle with a sides of 7 and 15. so lets find the area of this rectangle
A=L*W
A=15*7
A=105
now combine the two areas
67.5+105
172.5
so answer "C"
Answer:
Hence the correct option is the last one . The triangle is an obtuse angled triangle.
Step-by-step explanation:
i) the sum of any two sides added together is greater than the third side hence this is a triangle.
ii) it is<em><u> not</u></em> a right angled triangle as 
and 
iii) the triangle is not acute from ii) above
iv) the triangle is an obtuse triangle from ii) above.
I don’t see any of the problems so I’m guessing you would have to rewrite it
Answer:
Step-by-step explanation:
Triangle IGH is a right angle triangle.
From the given right angle triangle
GH represents the hypotenuse of the right angle triangle.
With ∠G as the reference angle,
GI represents the adjacent side of the right angle triangle.
HI represents the opposite side of the right angle triangle.
To determine GH, we would apply Pythagoras theorem which is expressed as
Hypotenuse² = opposite side² + adjacent side²
GH² = 45² + 28²
GH² = 2025 + 784 = 2809
GH = √2809 = 53
To determine Cos G, we would apply trigonometric ratio
Cos θ = opposite side/hypotenuse. Therefore,
Cos G = 28/53
Cos G = 0.53
I’m also stuck on this question
