So if 2 is the first term then if n=1 then n+1=sequence so far but
second term is 9 so if n=2 then the 2nd term=9
you must use trial and error to find
so it is
7n-5 so if n=1 then
7(1)-5=7-5=2
if n=2 then
7(2)-5=14-5=9
sucess
the equation is 7n-5
No they wouldn’t because height dosent work at a steady pace
Answer:
A. P(EC) = 0.4
B. P(E∪E) = 0.75
C. P(EC ∩ FC) = 0.25
Step-by-step explanation:
Let us calculate -:
we are given with - P(E) = 60 and P(F) =.15,
Thus , (a) 


(b) P(E∪F) = P(E) + P(F)
= 0.60 + 0.15
= 0.75
(c)
∩
∪ 
= 
Hence , the answers are -A. P(EC) = 0.4 , B. P(E∪E) = 0.75 , C. P(EC ∩ FC) = 0.25.
I can’t answer if you don’t show the multiple choice...
F(x)=y=(2x-2)/4
f^-1(x)=x=(2y-2)/4
4x=2y-2
4x+2=2y
f^-1(x)=y=2x+1
f^-1(3)=2(3)+1
=6+1
=7