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maksim [4K]
3 years ago
14

On a map, the distance between two

Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0
131.25 miles.

If 1 inch actually equals 25 inches, then you can just multiply 5.25 inches by 25, and because 1 in is equivalent to 25 miles, then your final answer will be in miles
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I REALLY NEED HELP PLZ :(((((
liberstina [14]

Answer:

Where is the picture?

Step-by-step explanation:

5 0
3 years ago
Suppose that the sample standard deviation was s = 5.1. Compute a 98% confidence interval for μ, the mean time spent volunteerin
NISA [10]

Answer:

The 95% confidence interval would be given by (5.139;5.861)  

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

Assuming that \bar X =5.5 and the ranfom sample n=1086.

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=1086-1=1085

Since the Confidence is 0.98 or 98%, the value of \alpha=0.02 and \alpha/2 =0.01, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,1085)".And we see that t_{\alpha/2}=2.33

Now we have everything in order to replace into formula (1):

5.5-2.33\frac{5.1}{\sqrt{1086}}=5.139    

5.5+2.333\frac{5.1}{\sqrt{1086}}=5.861

So on this case the 95% confidence interval would be given by (5.139;5.861)    We are 98% confident that the mean time spent volunteering for the population of parents of school-aged children is between these two values.

5 0
3 years ago
Subtract 6q from 10z
Alla [95]

Answer:

10z-6q..............

7 0
3 years ago
Read 2 more answers
How many times larger is 1.9 × 10^-8 is than 4.2 × 10^-13<br><br>please help​
Jet001 [13]

Answer:

hope this helps!

Step-by-step explanation:

You have to divide:

1.9x10^-8 ÷ (4.2x10^-13)

= appr .45 x 10^5

= .45 x 100000

= appr 45,000 times as large

source: https://www.jiskha.com/questions/1857280/estimate-how-many-times-larger-1-9x10-8-is-than-4-2x10-13

credit: mathhelper

5 0
3 years ago
0.3(5x - 1.5) = 7.5 x= ?
vfiekz [6]

Answer:

x=5.3

Step-by-step explanation:

.3(5x-1.5)=7.5

1.5x-.45=7.5

1.5x=7.95

x=5.3

6 0
3 years ago
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