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3 years ago

-3x >18 values for x for inequality true

Mathematics

1 answer:

baherus [9]3 years ago

7 0

Answer:

x<-6

Step-by-step explanation:

-3x>18

x>18/-3

x>-6

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IgorC [24]

This answer seems to be C

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3 years ago

WXY is a right triangle. A. True. B. False.

lora16 [44]

Answer:

B. False

Step-by-step explanation:

According to pythagorean theorem, for this to be a right triangle, the sum of square of the length of the two legs must equal square of the length of the hypotenuse (longest side).

So $(\sqrt{34} )^{2}$ should equal $(\sqrt{18} )^{2}+(\sqrt{18} )^{2}$

We also know that $(\sqrt{a} )^{2}=(\sqrt{a})(\sqrt{a})=a$

Hence, $(\sqrt{18} )^{2}+(\sqrt{18} )^{2}=18+18=36$ , and

$(\sqrt{34} )^{2}=34$

They ARE NOT EQUAL, so the triangle is NOT a right triangle.

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3 years ago

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Answer:

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Step-by-step explanation:

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4 years ago

Three people are sitting on a bus. Belle is seated 4 meters directly behind Diego and 3 meters directly left of Reba. How far is

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3 years ago

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

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3 years ago