Use a Mohr circle to find the maximum shear stress relative to the axial stress.
Here we assume the axial stress is sigma, the transverse axial stress is zero.
So we have a Mohr circle with (0,0) and (0,sigma) as a diameter.
The centre of the circle is therefore (0,sigma/2), and the radius is sigma/2.
From the circle, we determine that the maximum stress is the maximum y-axis values, namely +/- sigma/2, at locations (sigma/2, sigma/2), and (sigma/2, -sigma/2).
Given that the maximum shear stress is 60 MPa, we have
sigma/2=60 MPa, or sigma=120 MPa.
(note: 1 MPa = 1N/mm^2)
Therefore
100 kN/(pi*d^2/4)=100,000 N/(pi*d^2/4)=120 MPa where d is in mm.
Solve for d
d=sqrt(100,000*4/(120*pi))
=32.5735 mm
Answer:
59
Step-by-step explanation:
5
12
27
41
51
59
=195/6=32.5
Answer:
She should offer a guarantee of 13.76 years.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The average life of a certain type of small motor is 10 years with a standard deviation of 2 years.
This means that 
If she is willing to replace 3% of the motors that fail, how long a guarantee (in years) should she offer?
She should offer the 100 - 3 = 97th percentile as a guarantee, so X when Z has a pvalue of 0.97, that is, X when Z = 1.88.




She should offer a guarantee of 13.76 years.
Answer:
find the middle point of the triangle
Step-by-step explanation:
Add up all the temperatures and divide by 4.
113/4=28.25
so if you need to round then 28.3 or just 28.