All categories

2 years ago

Determine whether the given value is a solution to the equation.

Mathematics

2 answers:

VARVARA [1.3K]2 years ago

6 0

A. No

5 + 15 = 20

B. Yes

33/3 (33 ÷ 3) = 11

C. No

5 × 7 = 35

Talja [164]2 years ago

4 0

Answer:

B) m/3=11 ; m=33

Step-by-step explanation:

First, I substituted in my 33 in the m in me m place. Then, divide 33 by 3 and you get 11=11, and that is a true statement. I hope this helps :)

You might be interested in

The sum of two numbers is -3 and their difference is 9 find the numbers

photoshop1234 [79]

Answer:

-6 and 3

Step-by-step explanation:

3-(-6)=3 +6=9 (two negative signs= positive sign)

-6 +3 = -3

It you have 6 negative tiles and add 3 positive tiles, the 3 negative tiles cancel 3 positive tiles. So hat is left is 3 negative tiles

7 0

3 years ago

If A = (0,2,3,4,9,11), B = {2,3,6,8,9,10) and C= {0,2,3,9), then (A-B) n(A-C) is

timofeeve [1]

Answer:

(A-B)n(A-C) ={ }

Wishing a nice day.

8 0

2 years ago

a shop sells three kinds of boots (football,rugby and hiking) sales are usually in the ratio 6:2:3 last month 24 pairs of footba

Hitman42 [59]

Answer:

Step-by-step explanation:

24 divided by 6= 4

2x4=8

3x4=12

24+8+12=44

3 0

3 years ago

Read 2 more answers

How many miles should a 2010 car have in 2019?

s344n2d4d5 [400]

In average, most cars are driven 15,000 miles per year. As of May 2014, a 2010 car should have around 70,000 miles on it.
Hope it helped!:)

7 0

3 years ago

The centers for disease control and prevention reported that 25% of baby boys 6-8 months old in the united states weigh more tha

melisa1 [442]

Answer:

0.1971 ( approx )

Step-by-step explanation:

Let X represents the event of weighing more than 20 pounds,

Since, the binomial distribution formula is,

$P(x)=^nC_r p^r q^{n-r}$

Where, $^nC_r=\frac{n!}{r!(n-r)!}$

Given,

The probability of weighing more than 20 pounds, p = 25% = 0.25,

⇒ The probability of not weighing more than 20 pounds, q = 1-p = 0.75

Total number of samples, n = 16,

Hence, the probability that fewer than 3 weigh more than 20 pounds,

$P(X$

$=^{16}C_0 (0.25)^0 (0.75)^{16-0}+^{16}C_1 (0.25)^1 (0.75)^{16-1}+^{16}C_2 (0.25)^2 (0.75)^{16-2}$

$=(0.75)^{16}+16(0.25)(0.75)^{15}+120(0.25)^2(0.75)^{14}$

$=0.1971110499$

$\approx 0.1971$

3 0

3 years ago