(a)Two charges are placed on the x-axis: one is placed at x = 3 m and the other is at x = -3 m. The magnitude of both charges is 2.3 µC but the blue one (at x = -3 m) is positive while the red one (at x = +3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(b) Now the positive and negative charge switch places. The magnitude of the charges is still 2.3 µC where the blue one (now at x = +3 m) is positive and the red one (now at x = -3 m) is negative.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(c) Now both charges (still at x = -3 m and x = +3 m) are positive. The magnitude of both charges is still 2.3 µC.
What are the x- and y-components of the electric field at (x, y) = (0 m, +4 m)?
(d) Finally, both charges (still at x = -3 m and x = +3 m) are negative. The magnitude of both charges is still 2.3 µC.
Answer:
Variation equation: y = k/√x
constant of variation: 200
Variation Equation by plugging the value of k: y = 200/√x
Step-by-step explanation:
If y varies inversely with the SQUARE ROOT of x, then;
y = k/√x
If x = 4, y = 100.
100 = k/√4
100 = k/2
200 = k
k = 200
Substitute into the expression
y = k/√x
y = 200/√x
Step-by-step explanation:
x⁴ − 5x³ + 11x² − 25x + 30
x⁴ − 5x³ + 6x² + 5x² − 25x + 30
x² (x² − 5x + 6) + 5 (x² − 5x + 6)
(x² + 5) (x² − 5x + 6)
(x² + 5) (x − 2) (x −3)
The zeros are 2, 3, and ±√5i.
Answer: x=sqrt10-2, x=-sqrt10-2
Step-by-step explanation: square root both sides of the equation.
x+2=sqrt10,-sqrt10
subtract 2 from both sides of the equation
x=sqrt10-2, -sqrt10-2
Answer:
Total is 5 hours.
Step-by-step explanation:
... in the attached picture.
Hope this helps!
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