Answer:
The number of houses built in Town B is 56.
Step-by-step explanation:
We are given that in 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B.
Also, 70 houses were built in Town A during 210.
Let the number of houses built in Town B be 'x'.
So, according to the question;
Number of houses built in Town A = Number of houses built in Town B + 25% of the houses built in Town B
x = 56
Hence, the number of houses built in Town B is 56.
Answer:
<u>Part 1: C. $3,159.30</u>
<u>Part 2. C. –5; –135; –10,935</u>
Step-by-step explanation:
Part 1:
Price of the boat = $ 16,600
Depreciation rate = 14% = 0.14
Time of utilization of the boat = 11 years
Price of the boat after 11 years = Original price * (1 - Depreciation rate)^Time of utilization of the boat
Price of the boat after 11 years = 16,600 * (1 - 0.14)¹¹
Price of the boat after 11 years = 16,600 * 0.1903
<u>Price of the boat after 11 years = $ 3,159.30</u>
Part 2:
Let's find out the first term of the sequence given:
A(1) = -5 * 3¹⁻¹
A(1) = -5 * 1
A(1) = -5
Let's find out the fourth term of the sequence given:
A(4) = -5 * 3⁴⁻¹
A(4) = -5 * 3³
A(4) = -5 * 27
A(4) = -135
Let's find out the eighth term of the sequence given:
A(8) = -5 * 3⁸⁻¹
A(8) = -5 * 3⁷
A(8) = -5 * 2,187
A(8) = -10,935
The ten thousandth number in 14,620 is 1
the number to the right of 1 is 4
4>5
The answer is 10,000
Answer:
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
Step-by-step explanation:
Given that;
mean x" = 5.4
standard deviation σ = 0.7
n = 6
Null hypothesis H₀ : μ = 5.0
Alternative hypothesis H₁ : μ > 5.0
∝ = 0.025
now,
t = ( 5.4 - 5.0) / ( 0.7/√6) = 0.4 / 0.2857 = 1.4
degree of freedom df = n-1 = 6 - 1 = 5
T critical = 2.571
Therefore; t < T critical,
Do no reject null hypothesis.
Conclusion:
there is no sufficient statistical evidence at 0.025 level of significance to support the claim.
