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ZanzabumX [31]
3 years ago
8

Prove the following relations:cot²a-cos²a=cot²a cosplease help:((​

Mathematics
1 answer:
Mademuasel [1]3 years ago
4 0

Answer:

steps below

Step-by-step explanation:

It's easier to prove from right side to left side. If you insist to prove from left to right, you can just reverse the calculation from bottom to the top.

cot^{2} a * cos^{2}a \\= cot^{2} a * (1-sin^{2} a)\\= cot^{2} a - cot^{2} a*sin^{2} a\\= cot^{2} a - \frac{cos^{2} a}{sin^{2}a} *sin^{2} a\\= cot^{2} a - cos^{2} a

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6 libras de café y 5 de azúcar costaron 227 pesos y 5 libras de café y 4 libras de azúcar (a los mismos precios) costaron 188 pe
nlexa [21]

Answer:

The price of one pound of coffee is 32 pesos

The price of one pound of sugar is 7 pesos

Step-by-step explanation:

The question in English is

6 pounds of coffee and 5 pounds of sugar cost 227 pesos and 5 pounds of coffee and 4 pounds of sugar (at the same prices) cost 188 pesos Find the price of one pound of coffee and one pound of sugar.

Let

x-----> the price of one pound of coffee

y-----> the price of one pound of sugar

we know that

6x+5y=227 -----> equation A

5x+4y=188 ----> equation B

Solve the system of equations by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution is the point (32,7)

see the attached figure

therefore

The price of one pound of coffee is 32 pesos

The price of one pound of sugar is 7 pesos

6 0
4 years ago
Please help me with this I'm stuck!!
Luden [163]

One half of a number x minus four is one-third times a number x plus two. :)

3 0
3 years ago
Read 2 more answers
There are thirteen animals in a barn. Some are chickens and some are pigs there are 40 legs in all. How many of each animal are
slega [8]
Hi. In order to solve this word problem, you must make two equations and solve them together. To make it easy, we will let the letter "p" represent the pigs and the letter "c" for the chickens. So our first equation will be:

p + c = 13

Now to count the legs - we know that pigs have 4 legs and chickens have 2 so our next equation will be:

2c + 4p = 40

Using the first equation we see that c = 13 - p Now we insert this into the second equation and solve:

2x(13-p) +4 pm = 40
26 - 2p + 4p = 40
2p = 14
p = 7 (there are 7 pigs so now we know there are 6 chickens.

Answer: 7 pigs and 6 chickens

I hope this helps.

Take care,
Diana
3 0
3 years ago
Suppose that a box contains 8 cameras and that 4 of them are defective. A sample of 2 cameras is selected at random. Define the
maria [59]

Answer:

P(x) = 8Cx * p^x * (1 - p)^(8 - r) ; r = 0, 1, 2

Step-by-step explanation:

Given that:

Total Number of cameras (n) = 8

Defective cameras = 4

X: number of defective cameras

For a binomial distribution :

P(x) = nCx * p^x * (1 - p)^(n - x)

Probability of success (p) on each trial is the same = (total number of samples / number of defective samples) = 8/4 = 0.5

If 2 samples are chosen at random :

Then, the binomial probability distribution will be :

P(x) = 8Cx * p^x * (1 - p)^(8 - r) ; r = 0, 1, 2

5 0
3 years ago
Order from least to greatest 0.5 0.41 3/5
FinnZ [79.3K]
Least. 0.41, 0.5, 3/5 Greatest
4 0
4 years ago
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