The circle with center O has two chords AC and EF which are of same length 9.07.
OD and OB are the two perpendiculars drawn from the center O to the two chords AC and EF .It represents the distance of the chords from the centre.
The circle theorem states: congruent chords are equidistant from the center.
OD is congruent to OB.
Option A is the right answer.
Answer:
Sorry im not sure on this one...
Step-by-step explanation:
a³ + b³ + c³ + 3abc = ( a + b + c)(a² + b² + c² + ab + bc + ca)
if a + b + c = 0. then a³ + b³ + c³ = 3abc
here a + b + c = 15 + (-9) + (-6)
a + b + c = 15 - 15
a + b + c = 0
so a³ + b³ + c³ = 3abc
15³ + (-9)³ + (-6)³ = 3(15)(-9)(-6)
= 2430
so the answer is 2430
Multiply by two
2/5 x 2/1 = 4/5
Answer:
these triangles some is 90°.
72°+2x=90°
2x=90°-72
2x=18
x=18/2
x=9
