The function will show exponential decay if one of the following is true
- the base is less than 1 and the exponent is positive
- the base is greater than 1 and the exponent is negative
The function that meets the requirement for exponential decay is ...

Answer:B
Step-by-step explanation:
1. X=41
2. x=17
3. x=25
4. x=81
Hope that helps
Answer:
<h3>Mean=3.5</h3><h3>Median=3.5</h3><h3>Range=6</h3><h3>Interquartile=1</h3>
Step-by-step explanation:
Given set of data is 0, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6
<h3>To find Mean , Median , Range and Interquartile range :</h3>
First finding Mean
<h3>Therefore Mean=3.5</h3><h3>Median:</h3>
- Since the number of observations is even, so the meadian becomes
-




<h3>Therefore Median=3.5</h3><h3>Range:</h3>
- Range=greatest value-least value
- In the given observations we have greatest value is 6 and least value is 0
- Therefore Range=6-0
<h3>Therefore Range=6</h3><h3>Interquartile:</h3>
- From the observations we have
and 


<h3>Therefore Interquartile=1</h3><h3 />