What is the distance between the points (3, 4) ( -2 , 4)

Of 24 tulips 1/3 are red. how many tulips are red?

Soloha48 [4]

6 tulips are red out of 24

3 0

4 years ago

Read 2 more answers

What's the right answer?

Masja [62]

Given:

$sinh(f(x))=1+x^2$

To find:

The value of f'(x).

Solution:

Formulae used:

$\dfrac{d}{dx}sinh(x)=cosh(x)$

$\dfrac{d}{dx}x^n=nx^{n-1}$

$\dfrac{d}{dx}C=0$

Chain rule:

$\dfrac{d}{dx}[f(g(x))]=f'(g(x))g'(x)$

Where C is an arbitrary constant.

We have,

$sinh(f(x))=1+x^2$

Differentiate with respect to x.

$cosh(f(x))f'(x)=0+2x$

$f'(x)=\dfrac{2x}{cosh(f(x))}$

Therefore, the required values is $f'(x)=\dfrac{2x}{cosh(f(x))}$ .

7 0

3 years ago

the sum of three numbers is 116. The first number is 6 more than the third. The second number is 3 times the third. What are the

Zigmanuir [339]

Answer:

107

Step-by-step explanation:

sum means addition so 3 + 6 = 9 116 - 9 = 107 hope it helps <3

7 0

3 years ago

Tarting at home, Emily traveled uphill to the hardware store for 60 minutes at just 6 mph. She then traveled back home along the

erik [133]

6+12=18

18÷2=9

Emilys average speed is 9mph

6 0

3 years ago

To plan the budget for next year a college must update its estimate of the proportion of next year's freshmen class that will ne

Naily [24]

Answer:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

$z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491$

$p_v =P(z>2.491)=0.0064$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=67 represent the applicants who request financial aid

$\hat p=\frac{67}{150}=0.447$ estimated proportion of applicants who request financial aid

$p_o=0.35$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of applicants who request financial aid is higher than 0.35.:

Null hypothesis: $p\leq 0.35$

Alternative hypothesis: $p > 0.35$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.447 -0.35}{\sqrt{\frac{0.35(1-0.35)}{150}}}=2.491$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(z>2.491)=0.0064$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of applicants who request financial aid is significantly higher than 0.35

5 0

3 years ago

What is the distance between the points (3, 4) ( -2 , 4)​

What is the distance between the points (3, 4) ( -2 , 4)