(-1,1) and (0,0) are probably it
Time from October 5 to January 16
T=26+30+31+16=103 days
I=1870*0.11*103/365=58.05
X = the number of months the tire was used
y = the thickness of the tire tread
y = -(3/7)x + 20
Substitute x for 20 (the number of months the tire was used) and solve for y.
The next question: Substitute x for 49 (the number of months the tire was used) and solve for y.
Answer:
Third option
Step-by-step explanation:
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<h3>They are 268 miles far apart after 4 hours</h3>
<h3>Further explanation</h3>
Acceleration is rate of change of velocity.
<em>a = acceleration ( m/s² )</em>
<em>v = final velocity ( m/s )</em>
<em>u = initial velocity ( m/s )</em>
<em>t = time taken ( s )</em>
<em>d = distance ( m )</em>
Let us now tackle the problem !
<u>Given :</u>
v₁ = 30 mph due east
v₂ = 60 mph due south
t = 4 hours
<u>Unknown :</u>
displacement = d = ?
<u>Solution :</u>
<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate