Answer:
x = 9/25, y = 7/25, z = 4/25
Explanation:
step 1: solve for y in first equation to use substitution
y = -2x + 1
step 2: insert into second equation to eliminate y variable and work with two variables
3(-2x+1) + z = 1 (now distribute)
-6x + 3 + z = 1 (bring over the -3)
-6x + z = -2
step 3: now left with -6x + z = -2 and x + 4z = 1, so eliminate z
-6x + z = -2 (multiply by 4)
4(-6x + z = -2)
-24x + 4z = -8
-
x + 4z = 1 (brought down third equation)
-25x = -9
x = 9/25
then just plug in x into the third equation to solve for z, followed by plugging it into the first equation to solve for y. you should end with y = 7/25 and z = 4/25
it means to have a great mind
Hopes This Help! :)
Answer:
Explanation:
Part D
For d, the very first thing you need to do is figure out which one of the steps you are going to use. You have 2 in b^2 + 2, so even if b = 0 the two still matters. It means that you use f(x) = -x + 3 because that's what you use when you have 2 or above.
The second thing you have to realize is that f(x) = -x + 3 has the meaning of what ever you see on the left in the place of x, you put on the right wherever there is an x.
In this case f(b^2 + 2) = -b^2 - 2 + 3 = 1 - b^2
I'm not sure enough to give you an answer for the domain and range, not this time of night.
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Answer:
Not sure....But I think it would be C....I had this once upon a time.