24/10 as a decimal on a math paper

My Notes The displacement from equilibrium of an oscillating weight suspended by a spring is given by y(t) = 1 4 cos(5t) where y

ikadub [295]

Answer:

y(0) = 0.25 feet

$y(\frac{1}{4}) = 0.0789 \text{ feet}$

$y(\frac{1}{2}) =-0.2003 \text{ feet}$

Step-by-step explanation:

We are given the following information in the question:

The displacement from equilibrium of an oscillating weight suspended by a spring =

$y(t) = \displaystyle\frac{1}{4} \cos(5t)$

where y is the displacement in feet and t is the time in seconds.

Here, cos is in radians.

1) t = 0

$y(0) = \displaystyle\frac{1}{4} \cos(5(0)) = \frac{1}{4} \cos(0) = \frac{1}{4}(1) = \frac{1}{4}$

y(0) = 0.25 feet

2) t = $\frac{1}{4}$

$y(\displaystyle\frac{1}{4}) = \displaystyle\frac{1}{4} \cos(5(\frac{1}{4})) = \frac{1}{4} \cos(1.25) = \frac{1}{4}(0.31532236) =0.07883059$

$y(\frac{1}{4}) = 0.0789 \text{ feet}$

3) t = $\frac{1}{2}$

$y(\displaystyle\frac{1}{2}) = \displaystyle\frac{1}{4} \cos(5(\frac{1}{2})) = \frac{1}{4} \cos(2.5) = \frac{1}{4}(-0.80114362) = -0.200285905$

$y(\frac{1}{2}) =-0.2003 \text{ feet}$

The negative sign indicates the opposite direction of displacement.

3 0

3 years ago

A boat takes 4 hours to go 20 miles upstream. It can go 32 miles downstream in the same time. Find the rate of the current and t

KonstantinChe [14]

Let the boat speed in still water be b.
Let the current speed be c.
The speed going upstream is 20/4 = 5 mph.
The speed going downstream is 32/4 = 8 mph.
b - c = 5 ........(1)
b + c = 8 .......(2)
Adding equations (1) and (2) we get:
2b = 13
b = 13/2 = 6.5
Plugging in the value for b into equation (1) we find c = 1.5.
The boat speed in still water is 6.5 mph and the current speed is 1.5 mph.

4 0

3 years ago

Solve the equation<br><br> (-7) (-5)

Tanzania [10]

The answer is 35 i think but i am not sure

6 0

3 years ago

Jean lives about 10 miles from the college where she plans to attend a 10-week summer class. There are two main routes she can t

jeka57 [31]

Answer:

We would advise her to choose Country Route because in this route time consistent between 15 and 18 minutes.

Step-by-step explanation:

We are given that Jean lives about 10 miles from the college where she plans to attend a 10-week summer class. There are two main routes she can take to the school, one through the city and one through the countryside.

Jean sets up a randomized experiment where each day she tosses a coin to decide which route to take that day. She records the following data for 5 days of travel on each route.

Country Route - 17, 15, 17, 16, 18 (in minutes)

City Route - 18, 13, 20, 10, 16 (in minutes)

Now, we have to decide which route is better for Jean to go to college.

As we can see from the data that the Country route timings is consistent between 15 to 18 minutes which means most of the times she will reach college between these minutes only.

While on the other hand, we can observe that City route timings are very much consistent as it has a low value of 10 minutes and high value of 20 minutes which means Jean can't be sure that at which time she will reach college.

Hence, we would advise her to choose Country route.

7 0

3 years ago

Lin lines the bottom of her first pan with aluminum foil. The area of the rectangular piece of foil 11 1 4 is square inches. Its

prisoha [69]

Answer:

Length =

= 5/2 inches or 2 1/2 inches

Step-by-step explanation:

Lin lines the bottom of her first pan with aluminum foil. The area of the rectangular piece of foil 11 1 4 is square inches. Its length is 4 1 2 inches. What is the width of the foil? Explain your reasoning.

Area of rectangle = Length × Width

Widths = Area/Length

The area of the rectangular piece of foil 11 1/4 is square inches.

Its length is 4 1 /2 inches.

Hence:

Length = 11 1/4 /4 1/2

= 45/4 ÷ 9/2

= 45/4 × 2/9

= 5/2 inches

= 2 1/2 inches

6 0

3 years ago