Answer:
Perimeter of polygon B = 80 units
Step-by-step explanation:
Since both polygons are similar, their corresponding sides and perimeters are proportional. Knowing this we can setup a proportion to find the perimeter of polygon B.

Let
be the perimeter of polygon B. We know from our problem that the side of polygon A is 24, the side of polygon B is 15, and the perimeter of polygon A is 128.
Let's replace those value sin our proportion and solve for
:





We can conclude that the perimeter of polygon B is 80 units.
Answer:
a = 4 cm
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
a² + 3² = 5²
a² + 9 = 25 ( subtract 9 from both sides )
a² = 16 ( take the square root of both sides )
a =
= 4
Answer:
d= -6
Step-by-step explanation:
56 = -8d + 8
1) You want to get d by itself. Subtract 8 from both sides.
56 = -8d + 8
- 8 - 8
<em>(8 - 8 = 0, and 56 - 8 is 48.)</em>
48 = -8d
2) Then, you divide my -8 on both sides.
(<em>48 / -8 is -6, and -8d / -8 is just d.)</em>
-6 = d
So, d = -6
Answer:
-5, -2, and 0
Step-by-step explanation: