Answer:
12.75 but thats what i got
Step-by-step explanation:
Answer:
Input Data :
Point 1(xA,yA)(xA,yA) = (4, 3)
Point 2(xB,yB)(xB,yB) = (3, -2)
Objective :
Find the distance between two given points on a line?
Formula :
Distance between two points = √(xB−xA)2+(yB−yA)2(xB-xA)2+(yB-yA)2
Solution :
Distance between two points = √(3−4)2+(−2−3)2(3-4)2+(-2-3)2
= √(−1)2+(−5)2(-1)2+(-5)2
= √1+251+25
= √2626 = 5.099
Distance between points (4, 3) and (3, -2) is 5.099
Answer:
3y = 2(x -8)
Step-by-step explanation:
this is the sol I could provide
Answer:
The last 3
Step-by-step explanation:
Since it's. 030 and nothing after that
Answer:
Slope is 2; y-intercept is (0,-6)
Step-by-step explanation:
Slope intercept form looks like 3y = 2x - 6
In the equation y=mx+b, M is always the slope, and B is always the y-intercept. Therefore if you look back at the problem the slope number should be in front of the x which makes it 2. Since the y-intercept is always b, y = -6.
Slope or m = 2; y-intercept is (0,-6)