We can use the pythagorean theorem to find x. The pythagorean theorem tells us to square each leg (height and base) of the triangle and add it. It should be equal to the hypotenuse square.

For this triangle it means, we square 6 and 3 and add it. It should be equal to x squared. Then we can solve. Shown below:

$6^2 + 3^2 = x^2\\36 + 9 = x^2\\45 = x^2\\x=\sqrt{45}$

<em>Now we can use property of radical $\sqrt{x}\sqrt{y} =\sqrt{x*y}$ to simplify:</em>

$x=\sqrt{45} \\x=\sqrt{5*9} \\x=\sqrt{5} \sqrt{9} \\x=3\sqrt{5}$

Correct answer is C

6 0

3 years ago

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Which system of equations can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x?

Sveta_85 [38]

$^{(1)}\ \ 4x^5-12x^4+6x=5x^3-2x\ \ ^{(2)}\\\\ \left\{\begin{array}{ccc}y=4x^5-12x^4+6x\ \ \ ^{(1)}\\y=5x^3-2x\ \ \ ^{(2)}\end{array}\right$

Answer: system nr 4.

7 0

3 years ago

The two lines intersected by the transversal are parallel.what is the value of x?

sattari [20]

I think it’s uhhhh i think it’s uhhh i thinks a carrot

8 0

3 years ago

Find the sum of (6d+5)-(2-3d)

devlian [24]

I think you have to combine like terms to solve this one. (6d - 3d) + (5 - 2) = 3d + 3

7 0

2 years ago