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gulaghasi [49]
3 years ago
10

Please help! I would appreciate it!!

Mathematics
1 answer:
AVprozaik [17]3 years ago
5 0

They are not congruent. Hope that is correct

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What is the answer to this equation [(3^2)^2]^4
Bad White [126]

Answer:

43,046,721

Step-by-step explanation:

Solve in the parentheses then go to the brackets.

3 to the 2nd power is 9

9 to the second power is 81

81 to the 4th power is 43,046,721.

3 0
3 years ago
Solve for x. x5x+15=1x+3 no solution −3 and 5 −3 5
Andrei [34K]

Answer:

-3

Step-by-step explanation:

5x + 15 = 1x + 3

Add -1x and -15 on both sides.

5x - 1x = 3 - 15

4x = -12

Divide 4 into both sides.

4x/4 = -12/4

x = -3

The solution for the equation is x = -3.

5 0
3 years ago
Find the domain and range of the relation if it is a
Mandarinka [93]
Domain: {3,4,6}
range: {-3,-1,4,8}
not a function
5 0
3 years ago
Read 2 more answers
Endpoint: (-4, 8), midpoint: (3,-4)<br><br> Find the other endpoint<br><br> Explain please
swat32

Answer: (10,-16)

Step-by-step explanation:

A(-4,8)\ \ \ \ C(3,-4)\ \ \ \ \ B(x_B,y_B)=?\\

See the graph below.

                             \displaystyle\\\boxed {x_C=\frac{x_A+x_B}{2} }\\\\

Multiply both parts of the equation by 2:

2x_C=x_A+x_B\\2x_C-x_A=x_A+x_B-x_A\\2x_C-x_A=x_B

Hence,

x_B=2*3-(-4)\\x_B=6+4\\x_B=10

                            \displaystyle\\\boxed {y_C=\frac{y_A+y_B}{2} }

Multiply both parts of the equation by 2:

2y_C=y_A+y_B\\2y_C-y_A=y_A+y_B-y_A\\2y_C-y_A=y_B

Hence,

y_B=2*(-4)-8\\y_B=-8-8\\y_B=-16\\Thus,\ B(10,-16)

4 0
2 years ago
I need your help, please!!!
bekas [8.4K]

Answer:

y=x+20

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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