Answer:
The constant force exerted on the ball by the wall is 119.68 N.
Step-by-step explanation:
Consider the provided information.
It is given that the mass of the ball is m = 2.2 kg
The initial velocity of the ball towards left is 7.4 m/s
So the momentum of the ball when it strikes is = 
The final velocity of the ball is -6.2 m/s
So the momentum of the ball when it strikes back is = 
Thus change in moment is: 
The duration of force exerted on the ball t = 0.25 s
Therefore, the constant force exerted on the ball by the wall is:

Hence, the constant force exerted on the ball by the wall is 119.68 N.
Answer:
A cross section parallel to the base is a square measuring 4 cm by 4 cm.
A cross section perpendicular to the base through the midpoints of opposite sides is a square measuring 4 cm by 4 cm.
A cross section that passes through the entire bottom front edge and the entire top back edge is a rectangle measuring 4 cm by greater than 4 cm.
Step-by-step explanation:
Cross sections parallel and Perpendicular to the base are squares 4 × 4
The diagonal cross section will be a rectangle with base 4 and height
sqrt(4² + 4²) = 4sqrt(2) > 4
Answer:
D
Step-by-step explanation:
You can see from the table that joules out = 4x moles in
for 32 moles 32 * 4 = 128 joules
Answer:
I got zero but I am not sure if that is right
Step-by-step explanation:
First what is the formula for a cone, and just simplify