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2 years ago

. Write 8% as a fraction or mixed number in simplest form.

Mathematics

2 answers:

lina2011 [118]2 years ago

7 0

Answer:

8/100 or 0.08

Step-by-step explanation:

A percent is always out of 100. I represented that in a fraction and a decimal, but both are out of 100. Hope this helped!

umka21 [38]2 years ago

6 0

8/100 or 0.08 hope this helps

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When Victoria goes bowling, her scores are normally distributed with a mean of 130

Artemon [7]

Answer:

0.2377 or about a 23.77% chance

Step-by-step explanation:

P(123<X<130) = normalcdf(123,130,130,11) = 0.2377303466 ≈ 0.2377

Therefore, the probability that the next game Victoria bowls, her score will be between 123 and 130 is 0.2377 or about a 23.77% chance

5 0

2 years ago

HELP I WILL MARK U BRAINEST what is (29/59)*(42/24)<br> btw / means divide

Ivahew [28]

Answer:

0.86.

Step-by-step explanation:

Calculator.

5 0

2 years ago

Read 2 more answers

Which choice is equivalent to the expression below?

alekssr [168]

Answer: OPTION A

Step-by-step explanation:

We need to remember that Product of powers property, which states that:

$(a^m)(a^n)=a^{(m+n)}$

Let's check the options:

A. For $5^9*5^{\frac{9}{10}}*5^{\frac{6}{100}}*5^{\frac{9}{1000}}$ you can apply the property mentioned before. Then:

$5^{(9+\frac{9}{10}+\frac{6}{100}+\frac{9}{1000})=5^{9.969}$

(It is the equivalent expression)

B. Add the exponents:

$5^9*5^{(\frac{9}{10}+\frac{9}{10}+\frac{6}{1000})=5^{10.806}$

(It is not the equivalent expression)

C. For $5^9*5^{\frac{96}{10}}*5^{\frac{9}{100}}}$ you can apply the property mentioned before. Then:

$5^{(9+\frac{96}{10}+\frac{9}{100})=5^{18.69}$

(It is not the equivalent expression)

D. We know that $5^{9.969}=9,290,347.808$ and we maje the addition indicated in this option, we get:

$5^9+5^{\frac{9}{10}}+6^{\frac{6}{100}}=1,953,130.37$

(It is not the equivalent expression)

6 0

3 years ago

Read 2 more answers

I get

dybincka [34]

Answer:

Absolute minimum = 1.414

Absolute maximum = 2.828

Step-by-step explanation:

$g(x,y)=\sqrt {x^2+y^2} \ constraints: 1\leq x\leq 2 ,\ 1\leq y\leq2$

For absolute minimum we take the minimum values of $x$ and $y$ .

$x_{minimum} =1\\y_{minimum}=1\\$

Plugging in the minimum values in the function.

$g(1,1)=\sqrt {1^2+1^2}\\g(1,1) = \sqrt{1+1}\\g(1,1)=\sqrt {2}\\g(1,1)=\pm 1.414\\$

Absolute minimum value will be always positive.

∴ Absolute minimum = 1.414

For absolute maximum we take the maximum values of $x$ and $y$ .

$x_{maximum} =2\\y_{maximum}=2\\$

Plugging in the maximum values in the function.

$g(2,2)=\sqrt {2^2+2^2}\\g(2,2) = \sqrt{4+4}\\g(2,2)=\sqrt {8}\\g(2,2)=\pm 2.828\\$

Absolute maximum value will be always positive.

∴ Absolute maximum = 2.828

3 0

3 years ago

4x^2-20=5 solve by using the square root property

riadik2000 [5.3K]

Step-by-step explanation:

4x^2 - 20 = 5

4x^2 -25 = 0

4x^2 = 25

2x = 5, or -5

x = 5/2 , or -5/2

7 0

3 years ago