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Shtirlitz [24]
3 years ago
8

18. The sum of 'l6, /3, and 'Is is

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0

Answer:

wn work

Step-by-step explanation:

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What is the range of possible sizes for side x? the other two sides are 8.0 and 8.5
kirza4 [7]

Answer: 0.5 < x < 16.5.

Step-by-step explanation:

Given: Two sides of triangle: 8.0 units and 8.5 units

Measure of third side = x

According to the triangle's inequality,

  • Sum of any two sides > third side.    (i)
  • Difference between the sides < third side.    (ii)

If x is the third side, then

x < 8+8.5   [Using (i)]

i.e. x< 16.5  

Also, x > 8.5-8   [Using (ii)]

i.e. x> 0.5

Hence, Range of possible sizes for side x would be 0.5 < x < 16.5.

8 0
3 years ago
C. The double shadedregion represents<br> of the whole.
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Step-by-step explanation:

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5 0
2 years ago
Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values
Vesnalui [34]

The Lagrangian is

L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)

with critical points where the partial derivatives vanish.

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}

L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda

L_\lambda=x^2+y^2-9=0

Substitute x,y into the last equation and solve for \lambda:

\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6

Then we get two critical points,

(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)

We get an absolute maximum of 3\sqrt{17}\approx12.369 at the second point, and an absolute minimum of -3\sqrt{17}\approx-12.369 at the first point.

4 0
3 years ago
Find the value of x that makes m||n​
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7x-23+11x+23=180
4x+0=180
4x/4=180/4
X=45

Answer: x=45
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3 years ago
Which shows the use of a credit card
kotykmax [81]
C is what you do when credit cards are involved.
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