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aliina [53]
3 years ago
7

Factor 9x^2 -5 . using difference of squares

Mathematics
1 answer:
lawyer [7]3 years ago
5 0
\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
9x^2-5\qquad 
\begin{cases}
9x^2=3^2x^2\\
\qquad (3x)^2\\
5=\sqrt{5^2}\\
\qquad (\sqrt{5})^2
\end{cases}\implies
\begin{array}{llll}
(3x)^2-(\sqrt{5})^2
\\\\\\
(3x-\sqrt{5})~(3x+\sqrt{5})
\end{array}
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Let's define the variables:

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