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kirill [66]
4 years ago
8

HELP WHAT DO I PUT.didjfhff

Mathematics
1 answer:
Tasya [4]4 years ago
4 0
Dang neither do I I’m trying to figure out what’s going on here sorry for not answering the questions
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What is the equation of a line that is parallel to x=−5 and that passes through the point (1,4)
anastassius [24]
Answer: x = 1

The given line x = -5 is a vertical line through -5 on the x axis. Every point on this line has an x coordinate of -5. Similarly, the line x = 1 has all of its points with x coordinate of 1. One of those points is (1,4). Any vertical line has an undefined slope. Any two vertical lines are parallel to one another.
8 0
3 years ago
Rewrite the expressions by using the distributive property and collecting like terms. 1/6(12s + 6)
Citrus2011 [14]

For the distributive property, multiply the number outside the parentheses by each term inside the parentheses.

1/6 x 12s = 2s

1/6 x 6 = 1

Now combine them to get the final answer: 2s + 1

4 0
3 years ago
Read 2 more answers
An Envelope from the post office is 3 inches wide with a total area of 30 in.² what is the height of the envelope
MrRa [10]
30/3=10 

Area= L x W
W= 3 
L= 10 

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3 years ago
Penny reads 12 pages in 1/2 hour. What is the unit rate for pages per hour? For hours per page
Tanya [424]
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8 0
3 years ago
$100 is deposited at the end of every week for five years in an account that pays 14%/an, compounded weekly. (8) What type of an
Rainbow [258]
Annuities whose payments are made at the end of the period are "ordinary annuity" type

\bf \qquad \qquad \textit{Future Value of an ordinary annuity}
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}
\end{array}
\\
pymnt=\textit{periodic payments}\to &100\\
r=rate\to 14\%\to \frac{14}{100}\to &0.14\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{weekly, thus}
\end{array}\to &52\\
t=years\to &5
\end{cases}
\\\\\\
A=100\left[ \cfrac{\left( 1+\frac{0.14}{52} \right)^{52\cdot 5}-1}{\frac{0.14}{52}} \right]
6 0
3 years ago
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