d) You have a <u>difference of squares</u>:
49y² - 9 = (7y)² - 3²
Recall the identity,
a² - b² = (a - b) (a + b)
So,
49y² - 9 = (7y - 3) (7y + 3)
e) Pull out the common factor 3 from each term:
3x² - 3x - 90 = 3 (x² - x - 30)
Now use the <u>sum-product method</u>. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so
3x² - 3x - 90 = 3 (x + 5) (x - 6)
f) Same as in (e), use the <u>sum-product method</u>. Notice that 42 = 7 • 6, and -7 - 6 = -13, so
x² - 13x + 42 = (x - 7) (x - 6)
Answer:
B
Step-by-step explanation:
A function can be graphed as a straight line, as long as it isn't vertical.
Answer:
Area of the garden:

Explanation:
Given the below parameters;
Length of the rectangle(l) = 23 ft
Width of the rectangle(w) = 14 ft
Value of pi = 3.14
Since the width of the rectangle is 14 ft, so the diameter(d) of the semicircle is also 14 ft.
The radius(r) of the semicircle will now be;

Let's now go ahead and determine the area of the semicircle using the below formula;

Let's also determine the area of the rectangle;

We can now determine the area of the garden by adding the area of the semicircle and that of the rectangle together;

Therefore, the area of the garden is 398.93 ft^2
Where is it shown? Please show a picture