Stewart has 18 birds remaining in avery. However he did have 29 until Tim left the door open. There are 8 blue birds and 4 Galah
1 answer:
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Answer:
A. 1/2 of a goal
Step-by-step explanation:
Hello!
Given the options:
A. 1/2 of a goal
B. 3/4of a goal
C. 1 goal
D. 4/3 goals
In a linear regression analysis the interpretation of the slope is:
> The modification of the average of Y when X increases one unit.
Given the variables
Y: Goals scored in the tournament.
X: Hours of training.
To calculate the slope, you have to use the y-intercept and choose two pairs of (Y;X) values that correspond to a value on the line, for example (1;1.5) and (2;1.5).
You can calculate the slope as b= ΔY/ΔX
1st value (X₁;Y₁)= (0;1)
2nd value (X₂Y₂)= (1;1.5)
So the average goals a player scores for every additional hour of practice is 1/2.
I hope this helps!
In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by
. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability
There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing possible hands. Exactly 2 aces are drawn in
hands. And so on. This gives a total of
possible hands containing at least 1 ace, and hence B occurs with probability
The product of these probability is approximately 0.000082.
A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. . This happens if
- the hand has 4 aces and 1 non-ace, or
- the hand has a non-ace 4-of-a-kind and 1 ace
The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So consists of 96 possible hands, which occurs with probability
and so the events A and B are NOT independent.