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8_murik_8 [283]
3 years ago
11

Find the angle measure and round to the nearest Tenth. cos0 = 7/10 x = ? degrees

Mathematics
1 answer:
Ad libitum [116K]3 years ago
5 0
I believe it is 45.6
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Step-by-step explanation:

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8 0
3 years ago
find the x intercepts of the parabola with the vertex (-3,405) and the y intercept (0,360). Write your answer in the form of (x1
Kipish [7]
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7 0
4 years ago
A square picture with side length 30 cm is scaled by 60% on a photocopier the copy is then scaled by 60% again. What is the side
Sonja [21]

Answer:

10.8 cm

Step-by-step explanation:

we know that

1) A square picture with side length 30 cm is scaled by 60% on a photocopier

Remember that

60\%=60/100=0.60

so

The length of the first copy of the picture is

30(0.60)=18\ cm

2) The copy is then scaled by 60% again

so

The length of the second copy of the picture is

18(0.60)=10.8\ cm

4 0
3 years ago
25A2B is a 5-digit number. If the number is divisible by 5 and 9, find all the possible values of A and B. Explain also.
3241004551 [841]

Answer:

25020, 25920, 25425

Step-by-step explanation:

To find if our number is divisible by 5 the number must end with 0 or 5, divisibility by 9 is if sum of all numbers in number is divisible by 9,

We know B must end with 0 or 5

1. Case 25A20 sum of that number is 9 so if we pick 0 as A we have first number because 9/9=1

We can put A as 9 because 18/9=2

2. Case B = 0, sum is 14 so we need pick A as 4 to get 18.

7 0
3 years ago
Ginny's piggybank contained $8.80 in quarters, dimes, and nickels. there were two more than five times as many nickels as quarte
SSSSS [86.1K]

Answer:

There are 13 quarters, 67 nickels, and 22 dimes.


Step-by-step explanation:

The value of a quarter is $0.25, the value of dime is $0.10, and the value of a nickel is $0.05. Let there be q quarters, n nickels, and d dimes.

Let's write equations from the statements given:


<u>"Ginny's piggybank contained $8.80 in quarters, dimes, and nickels.":</u>

0.25q+0.1d+0.05n=8.80

<u>"there were two more than five times as many nickels as quarters":</u>

5q+2=n

<u>"4 less than twice as many dimes as quarters":</u>

<u>2q-4=d</u>


Plugging in equation 2 and 3 into equation 1, we can solve for q:

0.25q+0.1(2q-4)+0.05(5q+2)=8.80\\0.25q+0.2q-0.4+0.25q+0.1=8.80\\0.7q=8.80+0.4-0.1\\0.7q=9.1\\q=\frac{9.1}{0.7}=13

<em>Substituting q = 13 into equation 2 will give us nickels:</em>

n=5q+2\\n=5(13)+2\\n=67

<em>Substituting q = 13 into equation 3 will give us dimes:</em>

d=2q-4\\d=2(13)-4\\d=22


There are 13 quarters, 67 nickels, and 22 dimes.

4 0
3 years ago
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