Answer:
Step-by-step explanation:
Given
Required
The difference quotient for h
The difference quotient is calculated as:
Calculate f(x + h)
The numerator of is:
Collect like terms
So, we have:
Rewrite as:
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1 answer:
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Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
Answer:
Step-by-step explanation:
We have been given that Vladimir is walking down the street at a speed of 4 miles per hour. We are asked to write an for the distance in miles, d, that Vladimir walks over time in hours, t.
We will use rate formula to solve our given problem.
Upon substituting our given information in distance equation, we will get:
Therefore, the equation represents the distance that Vladimir walks over time in hours.