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Lynna [10]
2 years ago
13

Write f(x)=x^2+2x-99 in standard form and please show your work

Mathematics
1 answer:
aliina [53]2 years ago
7 0

Answer:Write f(x)=x^2+2x-99 in standard form and please show your work

Step-by-step explanation:f

(

x

)

=

x

2

+

2

x

−

99

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Apply root test to the series.
Angelina_Jolie [31]
\displaystyle\lim_{n\to\infty}\sqrt[n]{\left|\left(\frac{5n+15}{2n-1}\right)^n\right|}=\lim_{n\to\infty}\frac{5n+15}{2n-1}=\dfrac52

Since this limit exceeds 1, the series diverges.
8 0
3 years ago
For what value of a is (a,9) a solution for the equation y=2x+1?
Ivahew [28]

Answer:

Step-by-step explanation:

(a,9).......we dont know " a " (or x) but we do know y...it is 9

so sub in 9 for y and solve for x

y = 2x + 1

9 = 2x + 1

9 - 1 = 2x

8 = 2x

8/2 = x

4 = x <======= ur answer is D

5 0
3 years ago
The area of Taylor’s square bedroom is 256 feet squared, what is the length of any side wall in his bedroom?
MAXImum [283]
The length of one side of his bedroom would be 16 feet.

The formula for area of a square is length x width and all four sides of a square are equal in length.

In this case 16x16 is equal to 256
6 0
3 years ago
Consider the following equation. f(x, y) = y3/x, P(1, 2), u = 1 3 2i + 5 j (a) Find the gradient of f. ∇f(x, y) = Correct: Your
BaLLatris [955]

f(x,y)=\dfrac{y^3}x

a. The gradient is

\nabla f(x,y)=\dfrac{\partial f}{\partial x}\,\vec\imath+\dfrac{\partial f}{\partial y}\,\vec\jmath

\boxed{\nabla f(x,y)=-\dfrac{y^3}{x^2}\,\vec\imath+\dfrac{3y^2}x\,\vec\jmath}

b. The gradient at point P(1, 2) is

\boxed{\nabla f(1,2)=-8\,\vec\imath+12\,\vec\jmath}

c. The derivative of f at P in the direction of \vec u is

D_{\vec u}f(1,2)=\nabla f(1,2)\cdot\dfrac{\vec u}{\|\vec u\|}

It looks like

\vec u=\dfrac{13}2\,\vec\imath+5\,\vec\jmath

so that

\|\vec u\|=\sqrt{\left(\dfrac{13}2\right)^2+5^2}=\dfrac{\sqrt{269}}2

Then

D_{\vec u}f(1,2)=\dfrac{\left(-8\,\vec\imath+12\,\vec\jmath\right)\cdot\left(\frac{13}2\,\vec\imath+5\,\vec\jmath\right)}{\frac{\sqrt{269}}2}

\boxed{D_{\vec u}f(1,2)=\dfrac{16}{\sqrt{269}}}

7 0
3 years ago
Can you put these in order (picture shown)
Svet_ta [14]
0.1/2.1 I hope that helps
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3 years ago
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