88.4*10^3 is = 88.4*10*10*10 =88400
Hope this helps! Any questions please just ask! Thank you!
So easyies way is find all multiplues of 6 that are less than 50
6
12
18
24
30
36
42
48
and not 42
6
12
18
24
30
36
48
more than 25
30
35
48
do not have a 3 in them
48
the answer is 48
Area = pi*r^2
Circumference = 2pi*r
Step 1: find the radius from area
81pi=pi*r^2
81=r^2
9=r
Step 2: plug in radius to the circumference equation
Circumference = 2pi*r
18pi is the answer, otherwise know as 56.52 as well.
We need to combine like terms, so 4x-3x, and 8y+2y. x+10y is it simplified
Step-by-step explanation:
We are told that for a large data set of a average student grades, the third quartile Q3 is found 78.5.
Since we know that third quartile represents the number such that 75% of the data is less than this number. Third quartile is the middle value between median and the highest value of a data set. Third quartile is also known as upper quartile. Third quartile splits lower 75% data from highest 25% of data.
Therefore, third quartile represents that 75% of student grades are less than 78.5 and 25% of students grades are greater than 78.5.
