Which pair of numbers is relatively prime?

The owner of a bakery wants to know whether customers have any preference among 5 different flavors of muffin. A sample of 200 c

Troyanec [42]

So,, there are 5 different flavors. A total of 180 people were asked. Hence, the hypothesis that there is no significant difference is that every flavor gets 180/5=36 flavors. x^2= $\sum{\frac{(x_i)^2}{m_i}}-n$ . In this case, mi is the proportion of the hypothesis, thus 36, n=180 and xi is the number of actual observations. Substituting the known quantities, we get that x^2=9. The degree of association is given by $\sqrt{X^2}/ \sqrt{N(n-1)}$ . This yields around 0.10, much higher than our limit.

8 0

3 years ago

Given that m∠ABD = 84° and m∠BAC = 37°, what is the m∠ACD?

stich3 [128]

Answer: 84°

Step-by-step explanation:

Pardon my drawing, I know it;s not prefect, and I'm not sure how to draw a figure on Brainly, but this is the best I can do. For this problem, it is easier to draw it out so you can see that the angles look like. Just pretend the lines are filled in, and this is a perfect parallelogram.

A ________________ C

/ /

B /_______________/ D

As you can see, the angles given in the problem gives us a parallelogram. Since we know m∠ABD is 84° and m∠BAC is 37°, we know that m∠ACD is 84°. If you draw diagonal lines, ∠ABD and ∠ACD are vertical angles. Vertical angles are congruent. Therefore, m∠ACD is 84°.

7 0

3 years ago

Simplify.<br>Enter your answer, in simplest form, (in the boxes).

zepelin [54]

Answer:

1/4

Step-by-step explanation:

5 0

3 years ago

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago

Find the value of In(-7).

jenyasd209 [6]

The answer is D

I’m right trust

4 0

3 years ago