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Ratling [72]
3 years ago
14

Which pair of numbers is relatively prime?

Mathematics
2 answers:
stiv31 [10]3 years ago
3 0
The answer tour question is D
Maslowich3 years ago
3 0
I think the answer would be c

You might be interested in
Select the values that make the inequality -c>-4 true.
Vera_Pavlovna [14]

Answer:

c < 4

Step-by-step explanation:

whenever you divide or multiply an inequality by a negative it is a rule that you must reverse the inequality symbol

so -c > -4 means you must divide or multiply by a negative one to get 'c' by itself; therefore it becomes c < 4

6 0
2 years ago
Give an example for a pair of alternate interior angles, a pair of corresponding angles, and a pair of alternate exterior angles
cluponka [151]

Answer:

One way to identify alternate exterior angles is to see that they are the vertical angles of the alternate interior angles.

Step-by-step explanation:

so if I was you I would use that strategy to try to find the pair of the Alternate exterior angles.

so the agles are probably 1 and 7 but i don’t want you to get it wrong so here’s a picture Of an example.

4 0
3 years ago
Part 3 - Discussion/Explanation Question
SpyIntel [72]

Step-by-step explanation:

Vertical asymptote can be Identites if there is a factor only in the denominator. This means that the function will be infinitely discounted at that point.

For example,

\frac{1}{x - 5}

Set the expression in the denominator equal to 0, because you can't divide by 0.

x - 5 = 0

x = 5

So the vertical asymptote is x=5.

Disclaimer if you see something like this

\frac{(x - 5)(x + 3)}{(x - 5)}

x=5 won't be a vertical asymptote, it will be a hole because it in the numerator and denominator.

Horizontal:

If we have a function like this

\frac{1}{x}

We can determine what happens to the y values as x gets bigger, as x gets bigger, we will get smaller answers for y values. The y values will get closer to 0 but never reach it.

Remember a constant can be represent by

a \times  {x}^{0}

For example,

1 = 1 \times  {x}^{0}

2 =  2 \times {x}^{0}

And so on,

and

x =  {x}^{1}

So our equation is basically

\frac{1 \times  {x}^{0} }{ {x}^{1} }

Look at the degrees, since the numerator has a smaller degree than the denominator, the denominator will grow larger than the numerator as x gets larger, so since the larger number is the denominator, our y values will approach 0.

So anytime, the degree of the numerator < denominator, the horizontal asymptote is x=0.

Consider the function

\frac{3 {x}^{2} }{ {x}^{2}  + 1}

As x get larger, the only thing that will matter will be the leading coefficient of the leading degree term. So as x approach infinity and negative infinity, the horizontal asymptote will the numerator of the leading coefficient/ the leading coefficient of the denominator

So in this case,

x =  \frac{3}{1}

Finally, if the numerator has a greater degree than denominator, the value of horizontal asymptote will be larger and larger such there would be no horizontal asymptote instead of a oblique asymptote.

8 0
2 years ago
Q. Mrs. Jackson purchased 8/9 lb of potatoes. She used 3/4 of the potatoes to prepare dinner. How much of the potatoes did Mrs.
kompoz [17]

Answer:

The answer is 5/36

Step-by-step explanation:

first, you are going to convert both of the fractions to have the same dinominator by multiplying by any of their factors.

32/36 - 27/36 = 536

Then you subtract the numerators and that's it

hope I helped :)


7 0
3 years ago
6,528 divided by 8 and also 6,349 divided by 9
mote1985 [20]

Answer:

6,528 divided by 8 is 816

6528/8 = 816

6348 divide by 9 is 705.44..... ♾️

7 0
3 years ago
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