Answer:
14 m²
Step-by-step explanation:
the height of the triangle is 3 m and the base is 4 m. 3 times 4 is 12 but then you have to half that so the area of the triangle is 6 m. The area of the rectangle is 2 times 4 which is 8. 8 plus 6 is 14. So 14 is your answer.
9514 1404 393
Answer:
7 square units
Step-by-step explanation:
There are several ways the area of triangle EBD can be found.
- find the lengths EB, BD, DE and use Heron's formula (messy due to roots of roots being involved).
- define point G at the lower left corner and subtract the areas of ∆DEG and BCD from trapezoid BCGE.
- figure the area from the coordinates of the vertices.
- use Pick's theorem and count the dots.
We choose the latter.
__
Pick's theorem says the area of a polygon can be found as ...
A = i + b/2 -1
where i is the number of grid intersection points interior to the polygon, b is the number of grid points intersected by the border.
The attached figure shows the lines EB, BD, and DE intersect one point in addition to the vertices. So, b=4. A count of the red dots reveals 6 interior points (i=6). So, the area is ...
A = 6 + (4/2) -1 = 7
The area of ∆EBD is 7 square units.
Answer:
66 can be made
1m left
Step-by-step explanation:

Ribbons that can be made= 66

length used= 99m
length remaining= 100m- 99m= 1m
The probability to choose letter n is

. After drawing letter n there left 25 letters and the probability to choose the letter w is

. After drawing two letters n and w there left 24 letters and then the probability to choose letter b is

. After drawing three letters n, w and b there left 23 letters, so the probability to choose letter t is

.
Using the product rule for probabilities, you can obtain that

.
Here, we are required to write a real-world problem that can be represented by the given equation
On the left hand side of the equation, we can say that :
The addition of 6 to twice my cousin's age which gives 2x+6.
On the right hand side, we can say the addition of 4 to thrice my cousin's age which also gives:
3x +4
Ultimately, the real-world problem may be in the form :
Six added to Twice my cousin's age is equal to 4 added to thrice his age.
Also, my variable, x represents my cousin's age.
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