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3 years ago

A number y cubed plus x squared decreased by 7

Mathematics

1 answer:

agasfer [191]3 years ago

5 0

Step-by-step explanation:

It is read thus Y^3+X^2-7

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What is 706 × 76? cuz u suck at math

blsea [12.9K]

53,656 is the answer.

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3 years ago

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Michael took in 91 mile bike trip. he left home at 7 AM. If he stopped for a total of two hours for rest and food and averaged 1

Korvikt [17]

Distance = rate * time
t = d / r

t = 91 / 14 = 6.5 hrs

plus 2 hour rest stop

8.5 hrs

start at 7 AM
end at 3:30 PM

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3 years ago

Melissa is making clothes for her dolls. She has 7/8 yard of fabric. Each doll shirt requires 2/7 of a yard of fabric. How many

igor_vitrenko [27]

Answer:

She can make three shirts and will have 7/56 left.

Step-by-step explanation:

49/56-14/56=35/56 (one shirt) 35/56-14/56=21/56 (two shirts) 21/56-14/56=7/56 (three shirts)

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3 years ago

If f(x) = 3x^0 - 2x^-1 +4 then f(2)=

Assoli18 [71]

Answer:

try this link

Step-by-step explanation:

https://www3.nd.edu › WorkPDF

Web results

MATH 10550, EXAM 1 SOLUTIONS 1. If f(2) = 5, f(3) = 2, f(4) = 5, g(2 ...

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3 years ago

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago