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3 years ago

HELP ASAP 1.A term that is a known number without variables. is called?

Mathematics

1 answer:

Natali5045456 [20]3 years ago

7 0

Answer:

constants

Step-by-step explanation:

Constants are the terms in the algebraic expression that contain only numbers. That is, they're the terms without variables. We call them constants because their value never changes, since there are no variables in the term that can change its value.

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The circle below is centered at the point (4,1) and has a radius of length 2. What is it’s equation?

vekshin1

Answer:

Option B:

$(x-4)^2+(y-1)^2 = 4$

Step-by-step explanation:

Given

Centre = (h,k) = (4,1)

Radius = r = 2

The standard equation of circle is:

$(x-h)^2+(y-k)^2=r^2$

Putting the values of h,k and r

$(x-4)^2+(y-1)^2 = (2)^2\\(x-4)^2+(y-1)^2 = 4$

Hence, the correct option is option B

$(x-4)^2+(y-1)^2 = 4$

5 0

3 years ago

Read 2 more answers

Mega Movies hosted a film premiere on Friday night. They charged $9 for adults and $6 for children. One hundred twenty-seven adu

Oxana [17]

x = number of adult tickets

y = number of children tickets

9x + 6y = 1053

x+y = 127 so x = 127 - y

replace x = 127 - y into 9x + 6y = 1053

9(127 - y) + 6y = 1053

1143 -9y + 6y = 1053

-3y = 1053 -1143

-3y = -90

y = 30

x = 127 - 30

x = 97

answer: 97 adults and 30 children

3 0

3 years ago

Shop only had 2 types of stamps left using

saveliy_v [14]

Answer:

{3¢, 28¢} or {4¢, 19¢} or {7¢, 10¢}

Step-by-step explanation:

54 = 1×54 = 2×27 = 3×18 = 6×9

Possible values of the stamps are 1 more than the values of a pair of factors. Of course, a 2¢ and 55¢ stamp will not permit paying 54¢ in postage, so that combination won't work. However, other pairs that will work are ...

3¢ and 28¢
4¢ and 19¢
7¢ and 10¢

7 0

3 years ago

Which conversion factors are used to multiply to 18cm/ s to get meters per minute?

Nimfa-mama [501]

Remark

The short answer is you multiply 0.6 times the cm/s to get m/min.

Solve

Though you didn't ask for it, here's the way it is done. Notice that each set of brackets cancels the units of a set of brackets to the left of the set of brackets you are observing. This is called unit analysis. The answer is given below.

$\frac{18 cm}{sec} *[\frac{60 cm}{1 min}] * [\frac{1 m}{100 cm}] = 18*0.6\frac{m}{min}=10.8\frac{m}{min}$

8 0

3 years ago

3(x + 4) + 2 = 2 + 5(x – 4) what is the fifth step in solving this equation.

kotegsom [21]

3(x+4)+2= 2+5(x-4)

3x+12+2= 2+ 5x-20

3x+14= 5x-18

3x+14-14= 5x-18-14

3x= 5x-32

3x-5x = 5x-32-5x

-2x= -32

-2x/ -2= -32/-2

x= 16

So answer A combine

8 0

3 years ago