Let x = length and y = width
You would have 2 lengths, so 2x and 3 widths, so 3y
Those need to equal total length of fence:
2x + 3y = 1200
The 3 widths would equal total fence minus the 2 lengths:
3Y = 1200-2x
Solve for y: y = 400 -2/3x
Area = length x width = xy. Replace y :
Area = x(400-2/3x) = 400x-2/3x^2
Differentiate:
400-4x/3 =0
4x/3 = 400
4x = 1200
X = 300
Y = 400-2/3(300) = 200
The dimension would be 300 ft x 200 ft
B: 140 fruit slices 70 minus 35 equals 35 right? Add 70 to 35, and that's 105 which is in the table. 105+35=140
Hope it helps
Step-by-step explanation:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
Yes you could because the obtuse angle is greater than 90 degrees so if the acute angle is inside the obtuse you could get an right angle or an 90 degree angle
Answer:
90
Step-by-step explanation:
x
−
12
y
=
−
210
=
=
−
210
x
−
6
y
=
90
=
=
90
x
=
=
90
