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2 years ago

Which coffee shop charges more for coffee cups?

Mathematics

1 answer:

Nookie1986 [14]2 years ago

3 0

Answer:

Coffee Shop B charges .50 cents more.

Step-by-step explanation:

I evaluated the graph and concluded that Coffee Ship B charges .50 cents more.

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Which of the following best describes a regular polygon when the measure of each exterior angle is 90?

marin [14]

I would think A because regular quadrilaterals have 90-degree angles.

7 0

2 years ago

Read 2 more answers

First come first served

Lemur [1.5K]

Answer:

m-45=-78

25=x+9

x and y are proportional, because they are doubling the outcome every time by 3, so the slope would simplify to 1/4 very time.

Step-by-step explanation:

3 0

2 years ago

What percent of 143 is 95.1?

Aloiza [94]

Answer:

66.5%

Step-by-step explanation:

95.1/143*100=66.5%

4 0

2 years ago

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Please help with this question. I need an answer ASAP!! I need help! I don't understand this!

Romashka-Z-Leto [24]

Answer: 42°

<u>Step-by-step explanation:</u>

HJ is an angle bisector of ∠IHK so

∠IHJ ≅ ∠KHJ ⇒ m∠IHJ = m∠KHJ

3a + 6 = 5a - 18

6 = 2a - 18

24 = 2a

12 = a

∠IHJ = 3a + 6

= 3(12) + 6

= 36 + 6

= 42

8 0

2 years ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

4 0

2 years ago