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3 years ago

An inequality is written below

Mathematics

1 answer:

andrey2020 [161]3 years ago

6 0

Answer:

x > 28

Step-by-step explanation:

$\frac{x-4}{-3} 24\\x>24+4\\x>28$

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9 gal/s=_____qt/min

HACTEHA [7]

So 9 Gallons a second is 2160 Quarts a minute

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3 years ago

Identify next three numbers in this sequence: 2, 6, 3, 9, 6, 18, 15

kherson [118]

Answer:

45,42,126

multiply by 3

6 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

4 years ago

Homework #74

ollegr [7]

784 divide by 7 is 112 so answer 112

7 0

3 years ago

Sami cut 6 and three fourth inches off a long roll of paper if the row 36 and one third inches long how long was the original ro

cestrela7 [59]

Answer:

43 1 ÷12

Step-by-step explanation:

The computation of the length of the original roll of papers is shown below:

36 1 ÷3 and 6 3 ÷ 4 together

Now convert the above fractions into a number

36 1 ÷ 3 = 109 ÷3

And,

6 3 ÷4 = 27 ÷ 4

Now add these two numbers i.e.

109 ÷3 + 27 ÷ 4

= 436 + 81 ÷ 12

= 517 ÷12

= 43 1 ÷12

6 0

3 years ago