Answer:
Step-by-step explanation:
<u>Given function is:</u>
Put x = 4
So,
![f(4) = 4^4\\\\f(4) = 256\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=f%284%29%20%3D%204%5E4%5C%5C%5C%5Cf%284%29%20%3D%20256%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
16, think of 4 plus 4 plus 4 plus 4.
The reaction is missing and it's ;
N2H4 + H2 ---> 2NH3
It asks for the total pressure too.
Answer:
A) Rate of change for NH3 = 152 torr/h
B) The total pressure in the vessel will remain the same.
Step-by-step explanation:
N2H4 + H2 ---> 2NH3
1 mole of N2H4 yields 2 moles of NH3.
From the question, the rate given for N2H4 is 76 torr/h.
Thus, The rate of change for NH3 will be = 2 x 76 = 152 torr/h
Now, on the reaction side, 1 mole of N2H4 reacts with 1 mole of H2. So we have 2 moles on the left hand side.
While on the product side, 2 moles of NH3 are produced.
So the total pressure will remain the same because for every 2 moles on the reaction side, 2 moles are gotten on the product side.
Answer:
43rd term
Step-by-step explanation:
Arithmetic sequences are basically linear functions, so the same value is added every time. So, knowing that Asub1 is equal to one, and Asubn is equal to 169 we can take 169-1 and divide by our common difference. This is four as 5-1=4 and 9-5=4.
So, (169-1)/4=42.
This is however 42 terms after Asub1, so this would be the 43rd teen of the sequence!
12,176/24 = 1522/3 or 507 1/3
