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3 years ago

In this system of equations below solve for x 2x+2y=12 x-4y=6

Mathematics

1 answer:

vova2212 [387]3 years ago

5 0

Answer:

X = 6

y = 0

Step-by-step explanation:

use elimination method. Multiply (x -4y = 6) by -2.

2x + 2y = 12

-2x + 8y = -12

add them together

10y = 0

y = 0

plug in for y

x - 4(0) = 6

x = 6

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3 years ago

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skelet666 [1.2K]

Answer:

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4 years ago

Choose the correct simplification of the expression (-9a^3b^2c^10)^0

Flauer [41]

Option C: 1 is the simplification of the expression $\left(-9 a^{3} b^{2} c^{10}\right)^{0}$

Explanation:

The given expression is $\left(-9 a^{3} b^{2} c^{10}\right)^{0}$

We need to simplify the given expression.

Simplification:

To simplify the given expression, let us apply the exponent rule, $a^{0}=1$ where $a \neq 0$

Thus, the the exponent rule $a^{0}=1$ means that any value (except zero) to the power of zero is equal to one.

Thus, the expression $\left(-9 a^{3} b^{2} c^{10}\right)^{0}$ becomes,

$\left(-9 a^{3} b^{2} c^{10}\right)^{0}=1$

Therefore, the simplified expression is 1

Hence, Option C is the correct answer.

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3 years ago

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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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