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3 years ago

How do I answer this question for my advance algebra class (4,2) m=1/3

Mathematics

1 answer:

saw5 [17]3 years ago

7 0

Answer:

esto es la pendiente? verdad

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5/6k+2/3=4/3 <br> What is K? <br> I don't understand how to do these

Drupady [299]

First, subtract 2/3 from both sides and you get $\frac{5}{6} k = \frac{2}{3}$
Then multiply both sides by 6/5 and you get $k = \frac{4}{5}$

8 0

3 years ago

HELP it's a maths question worth 4 marks

Ksenya-84 [330]

a = 3, b= - 4 and c = - 4

expand the left side using FOIL

(2x + 1)(ax + b) = 2ax² + 2bx + ax + b = 2ax² + x(2b + a) + b

compare the coefficients of expressions on left and right sides.

compare 2ax² + x(2b +a) + b with 6x² - 5x + c

coefficients of x² terms → 2a = 6 ⇒ a = 3

coefficients of x terms → 2b + a = - 5 → 2b + 3 = - 5 → 2b = - 8 ⇒ b = - 4

constant terms c = b = - 4

4 0

3 years ago

You roll a number cube with 6 sides two times. What is the probability of rolling a number greater than 2 and an odd number?

svetoff [14.1K]

Answer:

lol you've asked like 10 probability questions in 20 minutes i wonder what chapter you're studying

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Let A(t) be the area of a circle with radius r(t), at time t in min. Suppose the radius is changing at the rate of drdt=6 ft/min

mylen [45]

Answer:

The rate of change is $108\pi$ ft^(2)/min

Step-by-step explanation:

The area of a circle is given by the following equation:

$A(t) = \pi r^{2}$

To solve this question, we have to realize the implicit differentiation in function of t. We have two variables, A and r. So

$\frac{dA(t)}{dt} = 2\pi r \frac{dr}{dt}$

We have that:

$\frac{dr}{dt} = 6, r = 9$ .

We want to find $\frac{dA}{dt}$

$\frac{dA(t)}{dt} = 2\pi*9*6$

$\frac{dA}{dt} = 108\pi$

Since the area is in square feet, the rate of change is in ft^(2)/min.

So the rate of change is $108\pi$ ft^(2)/min

5 0

3 years ago

Please help! alg 1! I really need a explaintion fastttt

Gelneren [198K]

Answer:

y = -5x +10
(0, 10)
(1, 5)
see attached

Step-by-step explanation:

1. Subtract 5x from both sides to put the equation in slope-intercept form:

y = -5x +10

2. The y-intercept is the point corresponding to x=0. The y-value when x=0 is the constant in the equation: 10. Then the point is ...

(x, y) = (0, 10)

You may notice this is one of the points listed in part 4, and is also used in question 3.

3. The x-value computed is 1; the y-value computed is 5. The point is ...

(x, y) = (1, 5)

You may notice this is one of the points listed in part 4.

4. See attached

7 0

3 years ago