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3 years ago

Please help! alg 1! I really need a explaintion fastttt

Mathematics

1 answer:

Gelneren [198K]3 years ago

7 0

Answer:

y = -5x +10
(0, 10)
(1, 5)
see attached

Step-by-step explanation:

1. Subtract 5x from both sides to put the equation in slope-intercept form:

y = -5x +10

2. The y-intercept is the point corresponding to x=0. The y-value when x=0 is the constant in the equation: 10. Then the point is ...

(x, y) = (0, 10)

You may notice this is one of the points listed in part 4, and is also used in question 3.

3. The x-value computed is 1; the y-value computed is 5. The point is ...

(x, y) = (1, 5)

You may notice this is one of the points listed in part 4.

4. See attached

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3 years ago

9. Given the point (6,-8) values of the six trig function.

lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10

$\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}$

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

$\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}$

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3 years ago

Write three different fractions that are less than 40%?

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1/5
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3 years ago

Read 2 more answers

GEOMETRY HELP ASAP!!!!!!!!!!!!!!!!!!!

vovangra [49]

Area of equilateral triangle = a^2/4 * √3 so side of triangle = a

but if area of equilateral triangle = area of square multiplied by √3 then area of square = a^2 / 4 so side of square = a/2

the ratio length of side triangle to length side of square = a: a/2 that means the side of triangle is doubled the side of square

answer
a) 2:1

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