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Alexxandr [17]
3 years ago
7

Plz help!!! Solve 6 (u - 4) - 8 = -6 (-4u + 6) -2u Combine like-terms before solving

Mathematics
1 answer:
Elan Coil [88]3 years ago
8 0
Combining like terms:
First do the first part which is 6(u-4)-8, you first distribute 6 to u and -4, 6u-24-8
-24-8=-32, 6u-32
Second part the same thing , distribute -6 to -4u and 6, (negative times a negative equals a positive) 24u-36-2u
24u-2u=22u

Solving:
6u-32=22u-36
Subtract 6u on both sides, -32=16u-36
Add 36 on both sides, 4=16u
Divide 16 on both sides
U=4/16 which is 0.25
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Two angles are supplementary. One measures (3x) degrees and the other measures 51 degrees.
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Answer:

a. 3x +51=180

x=43

b. 3(43)+51 =180 51 degrees; 129 degrees

Step-by-step explanation:

3x +51 =180

3x=180-51

3x=129

x=43

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How many ml in 0.006​
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Step-by-step explanation:

7 0
3 years ago
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The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.
mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

-----------

For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution  

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.96516 probability of a chipmunk living through the year, thus p = 0.96516

Item a:

  • Two is P(X = 2) when n = 2, thus:

P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

  • Six is P(X = 6) when n = 6, then:

P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

  • At least one not living is:

P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0
3 years ago
Solve for X (picture included)
Fynjy0 [20]

Answer:

x = 41

Step-by-step explanation:

(2x+20) + (2x-4) = 180 degrees

4x+16 = 180 degrees

4x = 164

x = 41

The two sides are supplementary and add up to 180 degrees.

6 0
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Alexa has 5 more dollars than Caitlin. Altogether, Alexa and Caitlin have 45 dollars. How much money does each young lady have?
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Caitlyn has 20$ and Alexa has 25$
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