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Alexxandr [17]
3 years ago
7

Plz help!!! Solve 6 (u - 4) - 8 = -6 (-4u + 6) -2u Combine like-terms before solving

Mathematics
1 answer:
Elan Coil [88]3 years ago
8 0
Combining like terms:
First do the first part which is 6(u-4)-8, you first distribute 6 to u and -4, 6u-24-8
-24-8=-32, 6u-32
Second part the same thing , distribute -6 to -4u and 6, (negative times a negative equals a positive) 24u-36-2u
24u-2u=22u

Solving:
6u-32=22u-36
Subtract 6u on both sides, -32=16u-36
Add 36 on both sides, 4=16u
Divide 16 on both sides
U=4/16 which is 0.25
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Consider the following.x = t − 2 sin(t), y = 1 − 2 cos(t), 0 ≤ t ≤ 8πSet up an integral that represents the length of the curve.
sweet [91]

The length of the parametric curve (call it <em>C </em>) is given by

\displaystyle\int_C\mathrm ds=\int_0^{8\pi}\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt

We have

x=t-2\sin t\implies\dfrac{\mathrm dx}{\mathrm dt}=1-2\cos t

y=1-2\cos t\implies\dfrac{\mathrm dy}{\mathrm dt}=2\sin t

Now,

\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2=5-4\cos t

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\displaystyle\int_0^{8\pi}\sqrt{5-4\cos t}\,\mathrm dt

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8 0
2 years ago
Can u plz help me?...
Westkost [7]

Answer:

a  4 1/5

b  7 7/24

Step-by-step explanation:

a  7/9 * 5 2/5

Change the mixed number to an improper fraction

7/9 * (5*5+2)/5

7/9 * 27/5

Rewrite

7/5 * 27/9

7/5 * 3

21/5

Change this back to a mixed number

5 goes into 21 4 times  (4*5 = 20 ) with 1 left over

4 1/5


b  1 3/4 * 4 1/6

Change to improper fractions

(4*1+3)/4  * (6*4+1)/6

7/4 * 25/6

175/24

Change back to a mixed number

24 goes into 175 7 times  (7*24 =168 ) with 7 left over

7 7/24

3 0
3 years ago
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Korolek [52]

Answer:

60 : 12

90 : 18

120 : 24

150 : 30

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2 years ago
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murzikaleks [220]

Answer: Option a) 3

Step-by-step explanation:

The formula for calculating combinations is as follows

nCr = \frac{n!}{r!(n-r)!}

Where "n" is the amount of items in a set and you can choose "r" from them

3C1 reads as: The combination of 1 in 3. You have a set of 3 elements and choose 1 of them.

n = 3\\\\r = 1

So :

3C1=\frac{3!}{1!(3-1)!}\\\\3C1=\frac{3!}{1!*2!}\\\\3C1=\frac{3*2*1}{1*2*1}\\\\3C1=3

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Answer:

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