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3 years ago

The neiman family went out to dinner. How much will they pass altogether if their dinner bill came to 78.52 and they tip 18%

Mathematics

1 answer:

nata0808 [166]3 years ago

3 0

That would be a $14.13 tip
so 78.52+14.12= 92.65
$92.65

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An oil exploration firm is formed with enough capital to finance ten explorations. The probabil- ity of a particular exploration

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Answer:

μ = 1 The firm expects that one oil exploration will be successful.

v(x)= 0.9

Step-by-step explanation:

The first step is to define the random variable x as:

x: number of oil explorations being succesful

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Then μ = 10*0.1 = 1

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Answer:

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Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

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The Corporate Lawyer, a magazine for corporate lawyers, reported that out of 200 firms with employee stock ownership plans, 150 indicated that the primary reason for setting up the plan was tax related.

This means that $n = 200, \pi = \frac{150}{200} = 0.75$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.}{2} = 0.975$ , so $Z = 1.645$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 - 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.6996$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.75 + 1.645\sqrt{\frac{0.75*0.25}{200}} = 0.8004$

As percent:

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The 90% confidence interval for the population proportion of all such firms with this as the primary motivation is (69.96%, 80.04%).

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3 years ago