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jekas [21]
3 years ago
6

2x+5=13 Help me out please

Mathematics
2 answers:
viva [34]3 years ago
8 0

Answer:

4

Step-by-step explanation: 2x+5=13

                                                  -5   -5

                                                   2x=8

                                                   /2     /2

                                                      x=4

Oliga [24]3 years ago
4 0

Answer:

X = 4

Step-by-step explanation:

Subract 5 from 5 and 13

Simplify: 2x = 8

divide both sides of the equation by the same term 2x/2 8/2

which gets you x = 4

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How do I factorise an expression
ololo11 [35]
It factorises to -
4(x+6)

3 0
3 years ago
If the perimeter of the adult pinball machine is 177 inches, what is the lenght, in inches of g'a'?
borishaifa [10]
The length of the paintball machine could vary. If it is a square; then it would be 44.25 in. If it was a rectangle the answer Could be many different lengths, but one is 65 in (Width 23.5 in) I hope this helped ^^
4 0
3 years ago
Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t
Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1.f(x)=\frac{x^2+x-20}{x^2+4}

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345

3.h(x)=\frac{3x-5}{x^2-5x+7}

x^2-5x+7=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43

2.g(x)=\frac{x-17}{x^2+75}

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12

4.i(x)=\frac{x^2-9}{x-9}

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is  not continuous on the set of real numbers.

5.j(x)=\frac{4x^2-7x-65}{x^2+10}

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0

6.k(x)=\frac{x+1}{x^2+x+29}

x^2+x+29=0

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102

7.l(x)=\frac{5x-1}{x^2-9x+8}

x^2-9x+8=0

x^2-8x-x+8=0

x(x-8)-1(x-8)=0

(x-8)(x-1)=0

x=8,1

The function is not defined for x=8 and x=1

Hence, function l is not  defined for all real values.

8.m(x)=\frac{x^2+5x-24}{x^2+11}

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

6 0
3 years ago
After 5 years, a $2,450 investment is worth $3,123.75.
kondaur [170]

Answer:

5.5%

Step-by-step explanation:

To solve this problem we can use a modified version of the simple interest formula which is shown below:

r=\frac{I}{Pt}

<em>I = interest amount</em>

<em>P = principal amount</em>

<em>t = time (years)</em>

<em />

The first step is to find the interest gained from the investment.

3,123.75-2,450=673.75

Next, plug in the values into the equation:

r=\frac{673.75}{(2,450)(5)}     Multiply the bottom values

r=\frac{673.75}{12,550}         Divide the values

r=.055

The last step is to convert 0.055 into a percent:

0.055(100)=5.5

The interest rate is 5.5%

3 0
3 years ago
What are the X and Y intercepts of y= -2(x-4)2 +3
kari74 [83]

Answer: x-intercepts are ( 2.775,0) and (5.225,0)

And y-intercept is (0,-29)

Step-by-step explanation:

Here the given equation is,

y = -2(x-4)^2+3

For x-intercept, y = 0,

Put y = 0 in the above equation of parabola,

We get, -2(x-4)^2 + 3 = 0

-2(x^2+16+8x) + 3 = 0

-2x^2-32-16x + 3 = 0

-2x^2-16x -29 = 0

By solving this equation,

We get, x = 2.775 or x = 5.225

Therefore, x-intercept of the given parabola are (2.775, 0) and (5.225,0)

Now, for y-intercept, x = 0

By putting x = 0 in the given equation of parabola,

We get, y = -29

Thus, y-intercept of the given parabola = (0,-29)



4 0
3 years ago
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