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3 years ago

13

Chitra spent $200 at a thrift shop. She bought 3 rings for $21 each and spent the rest on 4 equally price bracelets. How much di

d each bracelet cost?

1 answer:

meriva3 years ago

6 0

Cost of Rings = 3 x $21
= $63

Cost of Bracelets = $200 - $63
= $137

Cost per Bracelet = $137 / 4
= $34.25

Therefore, the answer is C

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Distinguish between an axoim and a theorem

Anton [14]

Answer:

An axiom is often a statement assumed to be true for the sake of expressing a logical sequence. ... These statements, which are derived from axioms, are called theorems. A theorem, by definition, is a statement proven based on axioms, other theorems, and some set of logical connectives.

Step-by-step explanation:

I think this is right, but don't quote me on this.

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3 years ago

Si un rectángulo con perímetro de 74 pulgadas tiene un largo de 5 pies más que el ancho,

baherus [9]

Perímetro del rectángulo = 74 pulgadas

Deje que el ancho del rectángulo sea 'x'.

Entonces, la longitud de este rectángulo = x + 5

We know that :

$\color{hotpink}\tt \: Perímetro \: del \: rectángulo =\color{plum} 2 × (l + b)$

Lo que significa :

$=\tt 2(x + x + 5) = 74$

$=\tt 2(2x + 5) = 74$

$=\tt 4x +10 = 74$

$=\tt 4x = 74 - 10$

$=\tt 4x = 64$

$=\tt x = \frac{64}{4}$

$\color{plum} =\tt x = 16$

Por lo tanto, el ancho de este rectángulo = 16 pulgadas

Entonces, la longitud de este rectángulo :

$=\tt x + 5$

$= \tt16 + 5$

$\color{plum} =\tt 21 \: pulgadas$

La longitud de este rectángulo = 21 pulgadas

<h2>Por lo tanto :</h2>

● Longitud del rectángulo = <em>21 pulgadas</em>

● Ancho del rectángulo = <em>16 pulgadas</em>

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In science class, the girl to boy ratio is 3 to 7.

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I would say that there are 29 boys in the class.

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Advocard [28]

Hello!

To find the surface area of a sphere you use the equation

$A = 4 \pi r^{2}$

A is surface area
r is radius which is half the diameter

Put in the values you know

$A = 4 \pi 6.25^{2}$

Square the number

$A = 4 \pi 39.0625$

Multiply the 4 and the 39.0625

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The answer is $B) 156.25 \pi in^{2}$

Hope this helps!

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3 years ago