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il63 [147K]
2 years ago
11

The graphs below have the same shape. What is the equation of the red graph? G(x)=___

Mathematics
1 answer:
aliya0001 [1]2 years ago
5 0

Answer:

g(x)= 4-x^{4}

Step-by-step explanation:

From the blue parabola, we would have to move up one unit to make the red parabola. This means that g(x)= 4-x^{4}.

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What do -4 (x+7)-4 equal
Dima020 [189]

Answer:

-4x-32  Can i please get a brainliest because this correct.

Step-by-step explanation:

−4(x+7)−4

Distribute:

=(−4)(x)+(−4)(7)+−4

=−4x+−28+−4

Combine Like Terms:

=−4x+−28+−4

=(−4x)+(−28+−4)

=−4x+−32

Answer:

=−4x−32

5 0
3 years ago
Given f (x) = 2x^2 -3x + 5, find f (-4)
bogdanovich [222]
-1=x is the answer I’m pretty sure
4 0
3 years ago
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X^2+4x+20=12x-5<br><br> Solve this equation
Scrat [10]

Answer:

4 + (or -) 3i

Step-by-step explanation:

Hi!

Alright, so we're going to move all of the variables and constants to one side. Then, using the quadratic formula, we'll find the answer.

1. Move 12x-5 to the left side of the equation by

  a. Subtracting 12x from both sides

  b. adding 5 to both sides.

1: x^2+4x+20-12x+5

2. Group the common terms

  x^2+4x-12x+20+5 --> x^2-8x+25

3. Look at the problem. We can't factor this.

Explanation for why this isn't factorable (you can skip this)

(1) 25 is positive, so its two factors will both be either positive or negative. We're looking for a negative 8, so let's go with negative.

(2) Factors of 25: 1 & 25, 5 &5

Seeing the problem? Ya, none of the factors of 25 sum to eight. So, instead, we're going to use the quadratic formula.

4.  So, the quadratic formula: \frac{-b+-\sqrt{b^2-4ac} }{2a}

Our equation is x^2-8x+25=0

a is the constant in front of the x^2

b is the constant in front of the x

c is the term without any x values

so, a=1, b=-8, and c= 25

Into equation:

\frac{8+-\sqrt{64-4(1)(25)} }{2a}=\frac{8+-\sqrt{64-100} }{2}=\frac{8+-\sqrt{-36} }{2}

8/2 = 4

sqrt(-36) = 6i

6i/2 = 3i (remember, we still have the two in the denominator)

4 + (or -) 3i

8 0
2 years ago
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Find the area of the figure sides meet at right angles 8 cm, 3cm, 4cm, 5cm, 9cm​
Ivenika [448]

Answer:

umm is it a quadrilateral

Step-by-step explanation:

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3 years ago
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Are these triangles congruent if so which method?
Vaselesa [24]

yes they are congruent with ASA

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