2 years ago

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=79°, and DB = 5.7 feet. Find the length of BC to the nearest tenth of a foot.

Mathematics

1 answer:

Sergio [31]2 years ago

8 0

Answer:

29.8728≈29.9 feet

Step-by-step explanation:

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miss Akunina [59]

Answer:

Scruffy is $2\frac{1}{8}$ inches longer than Fluffy.

Step-by-step explanation:

Length of Scruffy = $10\frac{1}{4}$ inches

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We have to calculate how much Scruffy is longer than Fluffy.

Difference of their lengths = $10\frac{1}{4}-8\frac{1}{8}$

= (10 - 8) + $(\frac{1}{4}-\frac{1}{8})$

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= 2 + $\frac{1}{8}$

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2 years ago

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Artyom0805 [142]

First write the equation:
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Then subtract five from both sides:

1/2x = 1

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x = 2

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The answer to the question is range

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a_sh-v [17]

Answer:

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Step-by-step explanation:

Move all terms not containing m to the right side of the inequality.

Inequality Form:

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