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slavikrds [6]
3 years ago
7

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=79°, and DB = 5.7 feet. Find the length of BC to the nearest tenth of a foot.

Mathematics
1 answer:
Sergio [31]3 years ago
8 0

Answer:

29.8728≈29.9 feet

Step-by-step explanation:

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Round 3,567 to the nearest ten​
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Answer:3,570

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2 years ago
Olivia has 48 slices of ham and 36 slices of cheese to make sandwiches.
serious [3.7K]

The greatest number of sandwiches that Olivia can make is 12.

3 slices of cheese will be on each sandwich

<u>Solution:</u>

Given that, Olivia has 48 slices of ham and 36 slices of cheese to make sandwiches.  

We have to find what is the greatest number of sandwiches that Olivia can make? And how many slices of cheese will be on each sandwich?

Let the number of sandwiches be "n"

Then, number of slices of ham per sandwich =\frac{48}{n}

And, number of slices of cheese per sandwich =\frac{36}{n}

As slices can’t be fractions, "n" should be a factor of 48 and 36. So now let us find H.C.F of 48 and 36 as we want greatest number of sandwiches that Olivia can make.

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, and 36

The common factors are those which appear on both factors of 48 and 36 are 1, 2, 4, 6, and 12.

Out of these common factors, 12 is the greatest

So, H.C.F of 48 and 36 is 12, which means n = 12

Then, number of cheese slices per sandwich =\frac{36}{12}=3

Hence, 12 sandwiches can be made with 3 slices of cheese per sandwich.

8 0
3 years ago
50 students live in a dormitory. The parking lot has the capacity for 30 cars. Each student has a car with probability 12 , inde
Maurinko [17]

Answer:

P(X is greater than 30) = 0.06

Step-by-step explanation:

Given that:

Sample proportion (p) = 0.5

Sample size = 30

The Binomial can be approximated to normal with:

\mu = np = 50 \times 0.5 \\ \\ \mu= 25

\sigma = \sqrt{np(1-p) } \\ \\  \sigma = \sqrt{50 \times (0.5)(1-0.5) } \\ \\ \sigma = 3.536

To find:

P(X> 30)

So far we are approximating a discrete Binomial distribution using the continuous normal distribution. 30 lies between 29.5 and 30.5

Normal distribution:

x = 30.5, \mu = 25, \sigma = 3.536

Using the z test statistics;

z = \dfrac{x - \mu}{\sigma}

z = \dfrac{30.5 - 25}{3.536}

z = \dfrac{5.5}{3.536}

z = 1.555

The p-value for P(X>30) = P(Z > 1.555)

The p-value for P(X>30) = 1 - P (Z< 1.555)

From the z tables;

P(X> 30) = 1 - 0.9400

Thus;

P(X is greater than 30) = 0.06

7 0
3 years ago
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