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slavikrds [6]
2 years ago
7

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=79°, and DB = 5.7 feet. Find the length of BC to the nearest tenth of a foot.

Mathematics
1 answer:
Sergio [31]2 years ago
8 0

Answer:

29.8728≈29.9 feet

Step-by-step explanation:

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