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3 years ago

5

Mathematics

1 answer:

natima [27]3 years ago

6 0

Answer:

4/16 because 5/20 is equivalent to 1/4. 4/16 is also equivalent to 1/4

Step-by-step explanation:

Divide 5/20= 1/4

Multiply 4 times the numerator and the denominator:

4 × 1 = 4

4 × 4 = 16

so we know 4/16 is equivalent to 5/20

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3/5 × -4/7 + 4/35 - 3/10 × 4/7

Annette [7]

Answer:

I think its -2/5 but not sure

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Mjnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnn

Radda [10]

I don't know what this is supposed to mean, but thanks for the free points! ;)

7 0

4 years ago

Solve for x<br> 4(1 - x) + 2x = -3 (x + 1)

Blababa [14]

Answer:

x = -7

Step-by-step explanation:

4(1 - x) + 2x = -3 (x + 1)

4 - 4x + 2x = - 3x - 3

- 4x + 2x + 3x = - 3 - 4

x = -7

8 0

3 years ago

Find the area of the shaded region

Sonja [21]

Area= base times height

8 times 5= 40

2*3=6

40-6=34

shaded area is 34cm ^2

6 0

2 years ago

If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12

Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

$\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}$

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

$\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta$

$\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x$

$\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}$

$\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta$

$\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x$

$\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}$

$\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}$

$\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}$

$\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}$

Therefore, the expression reduces to

$\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}$

$\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}$

$\;\;\;\;\;= \dfrac{49}{26}$

5 0

2 years ago