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Taya2010 [7]
3 years ago
5

Select all equations that are equivalent to 5x+(x+6)+3x

Mathematics
1 answer:
12345 [234]3 years ago
8 0

Whoops! It looks like your question was not part of an academic assignment. Since Brainly is only intended for homework questions, we had to remove it. Please keep the question feed clear of personal questions so other users can get the help they need. Thanks! ߷

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Help me fast pleasee
Vinil7 [7]

Answer:

y=3x

Step-by-step explanation:

hope it helped

5 0
3 years ago
What is the vintercept of the line whose equation is y= 1/2x-3​
klemol [59]

Answer:

The y-intercept of line is (-3)

Step-by-step explanation:

Given equation of line is given by y= \frac{1}{2}x-3​

The general equation of line is given y=mx+c

Where, m= slope of line

c= y-intercept of line

On comparing both the equation.

c=(-3)

OR

y-intercept is when x=0,

therefore,

y= \frac{1}{2}x-3​

y= \frac{1}{2}(0)-3​

y=(-3)

Thus, y-intercept of line is (-3)

8 0
3 years ago
Help me with this problem
ryzh [129]

Answer:

angle 1 = angle 3

= 180°-136°

=44°

= angle 3

3 0
3 years ago
Distribute and combine √12x(-1+√5
gladu [14]

Answer:

-2\sqrt{3x} + 2\sqrt{15x}

Step-by-step explanation:

8 0
3 years ago
Solve using the elimination method:<br> X-3y=7<br> 3x + 3y=9
sergij07 [2.7K]

Answer:

                        x=4\\\\y=-1

Step-by-step explanation:

Given Equation:

x-3y=7      Equation:1

3x + 3y=9     Equation:2

Dividing Equation:2 by '3' both the sides:

x+y=3      

or   x=3-y     Equation:3

Putting the vale of 'x' in Equation:1

                             x-3y=7

                          (3-y)-3y=7\\\\3-y-3y=7\\\\3-4y=7\\\\

Subtracting '3' both sides

                             -4y=7-3\\\\-4y=4

                                 y=\frac{4}{-4}

                                 y=-1

Putting value of 'y' in Equation:3

                                x=3-y

                                x=3-(-1)\\\\x=3+1\\\\x=4

The solution of the equations is :

                              x=4\\\\y=-1

7 0
4 years ago
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